Answer:
The mass of the cargo is 
Explanation:
From the question we are told that
The radius of the spherical balloon is 
The mass of the balloon is 
The volume of the spherical balloon is mathematically represented as
substituting values
The total mass the balloon can lift is mathematically represented as
where 
is the density of helium with a value of
and 
is the density of air with a value of
substituting values
Now the mass of the cargo is mathematically evaluated as
M1 = 750Kg, v1 = 10m/s
m2 = 2500Kg , v2= 0 (because in problem say cuz that object don t move).
The momentum before colision is equal with the momentum after colision:
m1v1 + m2v2 = (m1+m2)v3 => v3 is the velocity after colison and that s u want to caluclate for your problem
=> m1v1 = (m1+m2)v3 => v3 = m1v1/(m1+m2) now u should do the math i think v3 prox 2,4 but not sure u should caculate
Answer:
2156J
Explanation:
Given parameters:
Height of lift = 10m
Mass = 22kg
Unknown:
Work done by the machine = ?
Solution:
Work done is the force applied to move a body through a certain distance.
So;
Work done = Force x distance
Here;
Work done = mass x acceleration due to gravity x height
Work done = 22 x 9.8 x 10 = 2156J
Answer:
16.67m/s
Explanation:
Given parameters:
Distance Pete drove = 300m
Time taken = 18s
Unknown:
Speed = ?
Solution:
Speed is the distance traveled per unit of time.
It is mathematically expressed as;
Speed = 
Insert the parameters and solve;
Speed = 
= 16.67m/s
