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gregori [183]
3 years ago
11

Twice the sum of Paloma's age and 15 is 106. How old is Paloma?

Mathematics
2 answers:
Ivanshal [37]3 years ago
7 0

Answer:

121

Step-by-step explanation:

fredd [130]3 years ago
4 0

Answer: 121

Step-by-step explanation:

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Please help!! Cause I’m not smart
Reika [66]

Answer:

The answer is B

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find three consecutive even integers such that the sum of the first, twice the second, three times the third is -76. What is the
ss7ja [257]

Answer:

The numbers are -14,-13 and -12

Step-by-step explanation:

<u><em>The correct question is </em></u>

Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?

Let

x ----> the first consecutive integer

x+1 ---> the second consecutive integer

x+2 ---> the third consecutive integer

we have that

x+2(x+1)+3(x+2)=-76

solve for x

apply distributive property

x+2x+2+3x+6=-76

Combine like terms

6x+8=-76

subtract 8 both sides

6x=-76-8

6x=-84

Divide by 6 both sides

x=-14

so

x+1=-14+1=-13

x+2=-14+2=-12

therefore

The numbers are -14,-13 and -12

3 0
3 years ago
3. What is the value of (4/3)^3
Shtirlitz [24]

Answer:

64/27 = 2.37037037

Step-by-step explanation:

(4/3)^3

Calculate 4/3  to the power of 3 and get 64 /27

64/27

​  

7 0
3 years ago
X = 10<br><br> x = 2<br><br> x = two divided by five.<br><br> x = 11
KengaRu [80]

Answer:

x = 10

Step-by-step explanation:

You can try the answers to see which works. (The first one does.)

Or, you can solve for the variable:

Divide by 75

... (1/5)^(x/5) = 3/75 = 1/25

Recognize that 25 = 5^2, so ...

... (1/5)^(x/5) = (1/5)^2

Equating exponents, you have

... x/5 = 2

... x = 10 . . . . . multiply by 5

_____

You can also start by taking logarithms:

... log(75) +(x/5)log(1/5) = log(3)

... (x/5)log(1/5) = log(3) -log(75) = log(3/75) = log(1/25) . . . . simplify the log

... x/5 = log(1/25)/log(1/5) = 2 . . . . . simplify (or evaluate) the log expression

... x = 10 . . . . . multiply by 5

_____

"Equating exponents" is essentially the same as taking logarithms.

5 0
3 years ago
=
nlexa [21]
The is c for this question
4 0
2 years ago
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