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Olenka [21]
3 years ago
7

If 2 CH3OH + 3 O2 -> 2CO2 + 4 H2O was carried out in the laboratory and 219 g of water was produced, what would the percent y

ield be if the reaction started with 229 g of methanol in excess oxygen gas
Chemistry
1 answer:
ANEK [815]3 years ago
7 0

Answer:

Percent yield = 84.5 %

Explanation:

Given data:

Mass of methanol = 229 g

Actual yield of water = 219 g

Percent yield of water = ?

Solution:

Chemical equation:

2CH₃OH + 3O₂  →  2CO₂  + 4H₂O

Number of moles of methanol:

Number of moles = mass/ molar mass

Number of moles = 229 g/ 32 g/mol

Number of moles = 7.2 mol

Now we will compare the moles of water with methanol.

                        CH₃OH         :            H₂O

                            2               :               4

                           7.2             :           4/2×7.2 = 14.4 mol

Mass of water:

Mass = number of moles × molae mass

Mass = 14.4 mol × 18 g/mol

Mass = 259.2 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 219 g / 259.2 g × 100

Percent yield = 84.5 %

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Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) P₄(s) → HPO₃²⁻(aq) + PH₃(g) [acidic]
m_a_m_a [10]

The balanced chemical equation is :

5P₄ + 36OH → 12HPO₃⁻² (aq) + 8PH₃ (acidic)

Here the oxidation number of P changed from 0 to -3 in PH₃ and increases  from 0 to +3 in HPO₃⁻². When P₄ changes to PH₃ reduction reaction is taking place as there is addition of hydrogen and when P₄ changes to HPO₃⁻² oxidation takes place as there is addition of oxygen.

Thus clearly both reduction and oxidation are taking place.

Thus, we can infer that here P₄ is both oxidizing as well as reducing agent.

To know more about oxidation number here:

brainly.com/question/13182308

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5 0
2 years ago
Can someone please please help me out ?
GarryVolchara [31]

Answer:

4.823 x 10^-19 J

Explanation:

Energy is calculated by E = hv where h - Planck's constant in joule.s

v - frequency.

in this particular question the wave length is 4.12 x 10^-7 m. to exhaustively use this we need a relation between wave length & frequency. c=wv where C is approximately 3 x 10^8m/s

-v = c/w = 3x10^8m/s / 4.12 x 10^-7m = 7.28 x 10^14 Hz or 1/sec

now we can simply use Planck's constant in E=hv =

(6.626 x 10^-34) x (7.28 x 10^14Hz) = 4.823 x 10^-19 J.

6 0
3 years ago
how many grams of calcium chloride can be prepared from 60.4 G of calcium oxide and 69.0 G of hydrochloric acid and a double dis
Ksenya-84 [330]
Balanced equation: 
<span>CaO + 2 HCl --> CaCl2 + H2O </span>
<span>Calculate moles of each reactant: </span>
<span>60.4 g CaO / 56.08 g/mol = 1.08 mol CaO </span>
<span>69.0 g HCl / 36.46 g/mol = 1.89 mol HCl </span>

<span>Identify the limiting reactant: </span>
<span>Moles CaO needed to react with all HCl: </span>
<span>1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO </span>
<span>Because you have more CaO than that available, HCl is the limiting reactant. </span>

<span>Calculate moles and mass CaCl2: </span>
<span>1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2</span>
8 0
3 years ago
NH3 + HCl---&gt; NH4Cl What is the Chemical reaction
KATRIN_1 [288]

Answer:

A combination reaction

Explanation:

The chemical reaction between ammonia and hydrochloric acid as shown below:

         NH₃  +  HCl →  NH₄Cl

is a combination reaction.

In a combination reaction, two compounds combines together to give one compound.

A combination reaction is also known as a synthesis reaction.

A single product forms from tow or more reactants.

The driving force for such reaction is the large and negative heat of formation of the product.

5 0
3 years ago
What is the concentration created when 380.0g of Pb(NO3)2 is added to 330.0 mL of solution?
Juliette [100K]

The concentration of lead nitrate is 3.48 M.

<u>Explanation:</u>

The molarity can be found by dividing moles of sucrose by its volume in litres. We can find the number of moles of sucrose by dividing the given mass by its molar mass. Now we can find the moles as,

Here mass of Pb(NO₃)₂ is 380 g

Molar mass of Pb(NO₃)₂ is 331.2 g/mol

Number of moles = $\frac{given mass}{molar mass}

                              =  $ \frac{380 g }{331.2 g/mol}

                              = 1.15 moles

Volume in Litres = 330 ml = 0.33 L

Molarity = $\frac{Moles}{Volume (L)}

          = 3.48 mol/L or 3.48 M

So the concentration of lead nitrate is 3.48 M.

7 0
3 years ago
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