1. How much heat is required to melt 25.0 g of ice at 0°C?
1 answer:
Answer: The heat required to melt 25.0 g of ice at is 8350 Joules
Explanation:
Heat of Fusion tells us how much energy is needed to convert 1g of a solid to a liquid at the same temperature.
Q = Heat absorbed = ?
m = mass of ice = 25.0 g
L = Latent heat of fusion of ice = 334 J/g
Putting in the values, we get:
Thus heat required to melt 25.0 g of ice at is 8350 Joules
You might be interested in
Explanation: An element is represented in the form of where,
X = Symbol of the element
A = Atomic Mass of the element X
Z = Atomic Number of element X
Hence, For the element Justwondoricium,
Symbol = Jw
Atomic number = 120
Atomic Mass = 224
Now, Atomic number = Number of electrons = Number of Protons
Number of electrons = 120
Number of Protons = 120
and Atomic Mass = Number of neutrons + Number of protons
Number of neutrons can be calculated as we know atomic mass and number of neutrons, Putting the numbers we get
Number of neutrons = 224 - 120 = 104
The nearest noble gas to the element having atomic number 120 is Oganesson (Og), which has an atomic number of 118, so the next two electrons will be filled in the 8s orbital.
Electronic Configuration of Jw is
This electronic configuration lets us know about the location of the element in periodic table.
As the electron is entering the 8th shell, it belongs to the 8th period and as the last electron enters the s-orbital, it belongs to the S-block of the periodic table.
When the s-electrons are 1, it belongs to Group 1.
When the s-electrons are 2, it belongs to Group 2.
As this element has 2 s-electrons, it belongs to the Group 2.
Answer:
Explanation:
Hello,
In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:
Therefore the equilibrium temperature shows up as:
Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:
Best regards.