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ICE Princess25 [194]
3 years ago
9

1. How much heat is required to melt 25.0 g of ice at 0°C?

Chemistry
1 answer:
tigry1 [53]3 years ago
8 0

Answer: The heat required to melt 25.0 g of ice at 0^0C is 8350 Joules

Explanation:

Heat of Fusion tells us how much energy is needed to convert 1g of a solid to a liquid at the same temperature.

Q=m\times L

Q = Heat absorbed = ?  

m = mass of ice = 25.0 g

L = Latent heat of fusion of ice = 334 J/g

Putting in the values, we get:

Q=25.0g\times 334J/g=8350J

Thus heat required to melt 25.0 g of ice at 0^0C is 8350 Joules

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If 700 g of water at 90 °C loses 27 kJ of heat, what is its final temperature?​
Phoenix [80]

Answer:

If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also increases; and the same happens when either of the two decreases .). The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature, ΔT= Tfinal - Tinitial

In this case:

  • Q= 27 kJ= 27,000 J (being 1 kJ=1,000 J)
  • c=4.186 \frac{J}{g* C}
  • m=700 g
  • ΔT= Tfinal - Tinitial= Tfinal - 90 °C

Replacing:

27,000 J=4.186 \frac{J}{g* C}*400 g* (Tfinal - 90C)\\

Solving:

27,000 J=1,674.4 \frac{J}{C}* (Tfinal - 90C)

\frac{27,000 J}{1,674.4 \frac{J}{C}} =(Tfinal - 90C)

16.125 °C= Tfinal - 90 °C

Tfinal= 16.125 °C + 90 °C

Tfinal= 106.125 °C

<u><em>If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C</em></u>

3 0
3 years ago
Which one is more metallic? <br><br> A) Gold or B) Bismuth
Arlecino [84]

Answer:

Gold

Explanation:

Download pdf
6 0
3 years ago
Number of representative particles in 3 moles Sn
AURORKA [14]

Answer:

18.066 × 10²³ particles

Explanation:

Given data:

Number of moles of Sn = 3 mol

Number of representative particles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 3 mole of Sn:

3 × 6.022 × 10²³ particles

18.066 × 10²³ particles

5 0
3 years ago
As the Amplitude of the wave decreases what be does the frequency do​
Alexxx [7]

Answer: pic of the test

Explanation:

4 0
3 years ago
Options are upper left upper right bottom left bottom right for both problems please help!
polet [3.4K]

Answer:

(upper right) corner of the periodic table to the bottom left corner

6 0
3 years ago
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