Let n = 0, 1, 2, 3, 4, 5, 6, 7....
When n = 0 then 0^2 + 0 = 0. n = 1 we have 1^2 + 1 = 2. And when n = 2 we have 2^2 + 2 = 6. When n= 3 we have 3^2 + 3 = 12. When n = 4 we have 4^2 + 4 = 20. When n = 5 we have 5^2 + 5 = 30. When n = 6 = 6^2 + 6 = 42. And finally when n = 7 we have 7^2 + 7 = 56. So at n = 1, 2, ...7, ... Our values are = 2, 6, 12, 20, 30, 42, and 56. It is obvious that n is always an even number. Hence n^2 + n is always an even integer for all positive integers.
When n = -1 we have (-1)^2 - 1 = 0 when n = -2 we have (-2)^2 -2 = 2. When n = -3 we have (-3)^2 - 3 = 6. When n = -4 we have (-4)^2 - 4 = 16 - 4 =12. When n =-5 we have (-5)^2 -5 = 20. When n = -6 we have (-6)^2 - 6 = 30. When n = (-7)^2 - 7 = 42. Hence n^2 + n is always even for all integers
Answer:
16 percent
Step-by-step explanation:
Answer:
i may be wrong but i think its weaving
Step-by-step explanation:
sorry if its not right
Answer:
C
Step-by-step explanation:
Using Pythagoras' identity in right triangle BPO
with PB = 4 ( half of AB ) and OB = 5 ( radius of circle )
OP² + 4² = 5²
OP² + 16 = 25 ( subtract 16 from both sides )
OP² = 9 ( take the square root of both sides )
OP =
= 3
First Answer:
x = 12
First Step-by-step explanation:
12 + x = -3(4 - x)
12 + x = -12 + 3x
- x - x
—————————
12 = -12 + 2x
+ 12 + 12
—————————
24 = 2x
24/2 = 2x/2
12 = x
Second Answer:
No solution
Second Step-by-step explanation:
2(x - 1/2) = 8 + 2x
2x - 1 = 8 + 2x
+1 +1
—————————
2x = 9 + 2x
- 2x - 2x
—————————
0 = 9
^^ No solution