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dlinn [17]
3 years ago
9

Okay bro let’s go man yes yes

Engineering
2 answers:
r-ruslan [8.4K]3 years ago
8 0
Sheeeeeesh bro same name ayoooo??
docker41 [41]3 years ago
5 0

Answer:do me ti

Why not me

Why not me

do me ti

Why not me

Why not me

Do me ti

Why not me

Why not me

Explanation:

mitski

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What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 5
viva [34]

The approximate average power output is mathematically given as

P=1097.6w

<h3>What is the approximate average power output?</h3>

Question Parameters:

Iowa with a 10 m2 swept area and 50 m hub height

Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

Generally, the equation for the average output power  is mathematically given as

P=0.5 \phi BAu^3*n\\

Where

B= Benz coefficient

n=0.8

Therefore

P=0.5*1*0.8*10*7^3*0.8

P=1097.6w

For more information on Power

brainly.com/question/10203153

Complete Question

What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 50 m hub height? Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

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Why are there few effective HCI standards?
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A venturi meter is to be installed in a 63 mm bore section of a piping system to measure the flow rate of water in it. From spac
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Answer:

Throat diameter d_2=28.60 mm

Explanation:

 Bore diameter d_1=63mm  ⇒A_1=3.09\times 10^{-3} m^2

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Flow rate Q=240 Lt/min⇒ Q=.004\frac{m^3}{s}

Coefficient of discharge C_d=0.8

We know that discharge through venturi meter

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S_m=13.6 for Hg and S_w=1 for water.

h=0.235(\dfrac{13.6}{1}-1)

h=2.961 m

Now by putting the all value in

Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}

0.004=0.8\times \dfrac{3.09\times 10^{-3} A_2\sqrt{2\times 9.81\times 2.961}}{\sqrt{(3.09\times 10^{-3})^2-A_2^2}}

A_2=6.42\times 10^{-4} m^2

 ⇒d_2=28.60 mm

So throat diameter d_2=28.60 mm

     

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