To calculate the concentration of the base based on the titration, the concept used is the equal of number of equivalence of the acid used to that of the base. From this,
Na x Va = Nb x Vb
For HBr and KOH, molarity is equal to normality. Substituting the known values,
(0.75 M) x (22.6 mL - 0 mL) = Nb x (37.5 mL - 0.5 mL)
Nb = 0.46 N
Mb = 0.46 M
Thus, the concentration of the base is approximately 0.46 M.
The new volume is 1.9 ml
<u><em> calculation</em></u>
The new volume is calculated using the combined gas equation
that is P1V1/T1 = P2V2/T2 where
P1= 1.0 atm
V1= 21 ml
T1 = 10.0 c into kelvin = 10 + 273 = 283 k
P2 = 15 atm
V2=? Ml
T2 = 120 c into kelvin = 120 +273 = 393 K
make V2 the subject of the formula by multiplying both side by T2/P2
V2=T2P1v1 / P2T1
V2=[(393 k x 1.0 atm x 21 ml) / (15 atm x 283 K)] = 1.9 Ml
Answer:
Using the drop down Menu
Proton : Possessing a Charge of +1. It is found in the Nucleus and has a Mass of "A"
Neutron; Possesses a charge of 0. It is situated in the Nucleus and Has a Mass of "B"
Electron: Has a charge of -1. Found in the Orbitals of the atom and has a mass of "C"
