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faltersainse [42]
3 years ago
7

Which theory is a famous for quantum physics ​

Physics
1 answer:
crimeas [40]3 years ago
5 0
The quantum mechanics theory
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PLEASE HELP ME!!!!!!!!
Valentin [98]

i m soryyyyyyyyyyyyyy....

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4 0
3 years ago
(ik it says physics but astronomy is a field of physics sooo) A recently discovered planet in a different solar system is locate
marusya05 [52]

The distance, to the nearest tenth, is 314.9 light-years.

<em>The given data is:</em>

A recently discovered planet is located 1.85*10^5 miles from Earth.

Now we want to transform this distance to light-years.

Remember that a light-year is defined as "the distance that the light would travel in one year".

using the relation:

distance = speed*time

The speed of light is:

speed = 6.706*10^8 mi/h

And in one year has 8760 hours, then we have:

time = 8760 h

replacing these in the equation we get:

distance = speed*time

distance = (6.706*10^8 mi/h)*(8760 h)  = 5,874,456,000,000 miles

Son one light-year is equivalent to 5,874,456,000,000 miles

1 light-year = 5,874,456,000,000 miles

So to transform a distance in miles to light-years, we just need to divide that distance by 5,874,456,000,000 miles:

The distance between the new planet and Earth was:

D = 1.85*10^15 mi = ( 1.85*10^15)/(5,874,456,000,000) = 314.9 light-years.

if you want to learn more about this, you can read:

brainly.com/question/1302132

3 0
3 years ago
Calculate the recoil velocity in the horizontal direction, in meters per second, of a 1.25-kg plunger that directly interacts wi
mart [117]

Answer:

v_1=-8.19\ m/s'

Explanation:

It is given that,

Mass of the plunger, m_1=1.25\ kg

Mass of the bullet, m_2=0.0175\ kg

Initially both plunger and the bullet are at rest, u_1=u_2=0

Final speed of the bullet, v_2=585\ m/s

Let v_1 is the final speed of the plunger. Using the conservation of momentum to find it. The equation is as follows :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

Since, u_1=u_2=0

m_1v_1+m_2v_2=0

v_1=-\dfrac{m_2v_2}{m_1}

v_1=-\dfrac{0.0175\times 585}{1.25}

v_1=-8.19\ m/s

So, the recoil velocity of the plunger is 8.19 m/s. Hence, this is the required solution.

7 0
3 years ago
Help!!!! A loop of area 0.100 m^2 is oriented at 15.5 degree angle to a 0.500 T magnetic field. It rotates until it is at a 45.0
Nat2105 [25]

Answer:

Resulting Change in the Magnetic Flux =0.013\:Wb

Explanation:

Thanks!

3 0
3 years ago
A uniform magnetic field makes an angle of 30o with the z axis. If the magnetic flux through a 1.0 m2 portion of the xy plane is
Irina18 [472]

Answer:

(b) 10 Wb

Explanation:

Given;

angle of inclination of magnetic field, θ = 30°

initial area of the plane, A₁ = 1 m²

initial magnetic flux through the plane, Φ₁ =  5.0 Wb

Magnetic flux is given as;

Φ = BACosθ

where;

B is the strength of magnetic field

A is the area of the plane

θ is the angle of inclination

Φ₁ = BA₁Cosθ

5 = B(1 x cos30)

B = 5/(cos30)

B = 5.7735 T

Now calculate the magnetic flux through a 2.0 m² portion of the same plane

Φ₂ = BA₂Cosθ

Φ₂ = 5.7735 x 2 x cos30

Φ₂ = 10 Wb

Therefore, the magnetic flux through a 2.0 m² portion of the same plane is is 10 Wb.

Option "b"

3 0
3 years ago
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