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natta225 [31]
2 years ago
14

How long must a simple pendulum be if it is to make exactly one swing per four seconds? (That is, one complete oscillation takes

exactly 8.0 s.) Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
cricket20 [7]2 years ago
3 0

Answer:

Length of the pendulum will be 3.987 m

Explanation:

We have given time period of the pendulum T = 8 sec

Acceleration due to gravity g=9.81m/sec^2

We have to find the length of the simple pendulum

We know that time period of the simple pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

8=2\times 3.14 \sqrt{\frac{l}{9.81}}

l=3.987m

So length of the pendulum will be 3.987 m

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Find the tension in the two groups that are holding the 2.9 kg object in Pl., One makes an angle of 35.6° with respect to the ve
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Answer:

≈ 20.35 N [newton's of tension]

Explanation:

( (2.9 × 9.8) ÷ cos(35.6°) ) × sin (35.6°) =

( (28.42) ÷ (≈0.813) ) × (≈0.582) =

(≈34.96) × (≈0.582) = 20.3449446.... ≈ 20.35

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Calculating average speed
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Average speed =

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3 years ago
New seafloor is being created at point ______________.<br><br> 1. X<br> 2. Y<br> 3. Z<br> 4. None
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Answer:

Point x I think

Explanation:

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2 years ago
How are the movements of the Moon in the sky and Earth's rotation about its own axis related? A) The Moon appears to move from E
JulsSmile [24]

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3 years ago
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The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top
vaieri [72.5K]

Answer:

v = 44,16 m/s

Explanation:

We will fixate our reference in the starting point from where Dan jumped of, at the top of the Casino. Therefore, the displacement made when dan reached the airbag would be of y= -99,4 m viewed from our reference. We describe the motion of dan with the equation:

v_y^2 =v_0^2 +2ay

Dan jumped from the rest, that means that the initial velocity v_0=0, therefore:

 v_y^2 =2ay \rightarrow v_y = \sqrt{2ay}

Since Dan is moving in the negative axis regarding our reference point, we take the negative root of the equation.

v_y=-√(2*(-9,81 m/s^2 )*(-99,4 m) )=44,1613 m/s  v_y =- \sqrt{2*(-9,81 m/s^2)*(-99,4 m)} = 44,1613 m

So, if we don’t take the air resistance into account, Dan would have achieved an velocity of 44,16 m/s when he reached the airbag.

I hope everything was clear with my explanation. If you need anything else, let me know. Have a great day :D

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