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3 years ago

14

How long must a simple pendulum be if it is to make exactly one swing per four seconds? (That is, one complete oscillation takes

exactly 8.0 s.) Express your answer to two significant figures and include the appropriate units.

1 answer:

cricket20 [7]3 years ago

3 0

Answer:

Length of the pendulum will be 3.987 m

Explanation:

We have given time period of the pendulum T = 8 sec

Acceleration due to gravity $g=9.81m/sec^2$

We have to find the length of the simple pendulum

We know that time period of the simple pendulum is given by

$T=2\pi \sqrt{\frac{l}{g}}$

$8=2\times 3.14 \sqrt{\frac{l}{9.81}}$

$l=3.987m$

So length of the pendulum will be 3.987 m

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Answer:

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Explanation:

Given that,

Spring stiffness is

$k_{1}=20\ N/m$

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According to figure,

$k_{2}$ and $k_{3}$ is in series

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$\dfrac{1}{k}=\dfrac{1}{k_{2}}+\dfrac{1}{k_{3}}$

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$k=10\ N/m$

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$k'=10+20$

$k'=30\ N/m$

$k_{1}$ ,k' and $k_{5}$ is in series

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Using formula for series

$k_{eq}=\dfrac{1}{k_{1}}+\dfrac{1}{k'}+\dfrac{1}{k_{5}}$

Put the value into the formula

$k_{eq}=\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{35}$

$k_{eq}=8.93\ N/m$

Hence, The equivalent stiffness of the string is 8.93 N/m.

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