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Tpy6a [65]
4 years ago
8

When heating water, during what temperature range will the temperature cease to change for some time?

Physics
1 answer:
Morgarella [4.7K]4 years ago
7 0

Answer: Option (B) is the correct answer.

Explanation:

As we know that the temperature when the vapor pressure of liquid becomes equal to the atmospheric pressure surrounding the liquid. And, during this temperature liquid state of substance changes into vapor state.

But during this process of change in state of substance the temperature will cease to change for some time because unless and until all the liquid molecules do not convert into vapor state the temperature will not rise or change.

As the boiling point of water is 100^{o}C so the temperature ceases to change from 98^{o}C to 102^{o}C.

Therefore, we can conclude that when heating water, during 98^{o}C to 102^{o}C temperature range the temperature will cease to change for some time.

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450 nm of light falls on a single slit of width 0.30 mm. What is the angular width of the central diffraction peak
Andre45 [30]

Angular width is 3 x 10^-3

Let D be the distance between source and screed d the distance between coherent source then for central diffraction maxima,

where λ is wavelength

Given:

λ = 450 nm = 450×10^−9m

d = 0.3x10^−3m, D = 1m

W = 2 x 450×10^−9/0.3x10^−3*1

To Find:

Angular width

Solution: The width of the central maxima is nothing but the difference between the positions of the first two minima. Hence we will use the expression for the position of minima and accordingly obtain the expression of the width of central maxima and secondary maxima

θ = W/D

θ = 2 x 450×10^−9/0.3x10^−3*1/1 = 3 x 10^-3

Hence, angular width is 3 x 10^-3

Learn more about Angular width here:

brainly.com/question/25292087

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2 years ago
Consider the expression below. Assume m is an integer. 6m(2m + 18) Enter an expression in the box that uses the variable m and m
Anika [276]
6x2=12m
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12m+108
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