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BabaBlast [244]
2 years ago
11

Energy transformation in wound spring of a toy car?give your own answrr​

Physics
2 answers:
BaLLatris [955]2 years ago
7 0

Answer:

The work done in winding the spring gets stored in the wound up spring in the form of elastic potential energy (i.e potential energy due to change in shape). ... During this process, the potential energy stored in it gets converted to kinetic energy. This turns the wheels of the toy car.

Explanation:

KIM [24]2 years ago
4 0

Answer:

Both elastic potential energy and kinetic energy at t initial are converted to internal energy t f.

Explanation:

Apply the principle of Conservation of Energy to the system, where friction is present. Between t i and t f, the elastic potential energy in the spring and the kinetic energy of motion are being transformed into internal energy.

(I can't put t and f together because it got censored so that's why there is a space. Usually they are together.)

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I have absolutely no clue
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A new ride being built at an amusement park includes a vertical drop of 71.6 meters. Starting from rest, the ride vertically dro
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Explanation:

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3 years ago
A 1400 kg car starts from rest on a horizontal road and gains a speed of 61 km/h in 19 s. (a) what is its kinetic energy at the
lana [24]
(a) Let's convert the final speed of the car in m/s:
v_f = 61 km/h = 16.9 m/s
The kinetic energy of the car at t=19 s is
K= \frac{1}{2}mv_f^2= \frac{1}{2}(1400 kg)(16.9 m/s)^2=2.00 \cdot 10^5 J

(b) The average power delivered by the engine of the car during the 19 s is equal to the work done by the engine divided by the time interval:
P= \frac{W}{\Delta t}
But the work done is equal to the increase in kinetic energy of the car, and since its initial kinetic energy is zero (because the car starts from rest), this translates into
P= \frac{K}{\Delta t}= \frac{2.00 \cdot 10^5 J}{19 s}=1.05 \cdot 10^4 W

(c) The instantaneous power is given by
P_i = Fv_f
where F is the force exerted by the engine, equal to F=ma.

So we need to find the acceleration first:
a= \frac{v_f-v_i}{\Delta t}=  \frac{16.9 m/s}{19 s}=0.89 m/s^2
And the problem says this acceleration is constant during the motion, so now we can calculate the instantaneous power at t=19 s:
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5 0
3 years ago
Estimate how long it took King Kong to fall straight down from the top of the Empire State Building (380 m high). Express your a
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Answer:

It will take 8.80 sec to fall from the building

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So u = 0 m/sec

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We have to find the fall time

According to second equation of motion h=ut+\frac{1}{2}gt^2

So 380=0\times t+\frac{1}{2}\times 9.8\times t^2

t^2=77.55

t = 8.80 sec

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3 years ago
Scientists believe Earth is about how many billion years old
ehidna [41]
The earth is 4.54 billion years old.
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