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3 years ago

Identify the type of electrification of the road

Physics

1 answer:

Arte-miy333 [17]3 years ago

6 0

Electrification is widely considered as a viable strategy for reducing the oil dependency and environmental impacts of road transportation. In pursuit of this strategy, most attention has been paid to electric cars. However, substantial, yet untapped, potentials could be realized in urban areas through the large-scale introduction of electric two-wheelers.

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2.Cars were previously manufactured to be as sturdy as possible, whereas today's cars

Marina CMI [18]

Answer:

Crumple zones are designed to absorb and redistribute the force of a collision. ... Also known as a crush zone, crumple zones are areas of a vehicle that are designed to deform and crumple in a collision. This absorbs some of the energy of the impact, preventing it from being transmitted to the occupants.

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2 years ago

A battery charger is connected to a dead battery and delivers a current of 3.5 a for 4 hours, keeping the voltage across the bat

oksano4ka [1.4K]

The power delivered is equal to the product between the voltage V and the current I:
$P=VI=(16 V)(3.5 A)=56 W$

This power is delivered for a total time of $t=4h=4 \cdot 3600 s = 14400 s$ , so the total energy delivered to the battery is
$E=Pt = (56 W)(14400 s)=806400 J=806.4 kJ$

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3 years ago

What do you call the height of a wave?

Lina20 [59]

Answer:

amplitude is the answer

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3 years ago

Read 2 more answers

Froghopper insects have a typical mass of around 11.3 mg and can jump to a height of 58.8 cm. The takeoff velocity is achieved a

allochka39001 [22]

Answer:

2874.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{v^2-0^2}{2\times h}\\\Rightarrow v^2=2ah\ m/s$

Now H-h = 0.588 - 0.002 = 0.586 m

The final velocity will be the initial velocity

$v^2-u^2=2as\\\Rightarrow 0^2-u^2=2gs\\\Rightarrow -2ah=2\times g(H-h)\\\Rightarrow -2a0.002=2\times g0.586\\\Rightarrow a=-\frac{0.586\times -9.81}{0.002}\\\Rightarrow a=2874.33\ m/s^2$

Acceleration of the frog is 2874.33 m/s²

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3 years ago

A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0° above the horizontal. After it has

Novay_Z [31]

Answer:

3.07 m/s

Explanation:

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3 years ago