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andreev551 [17]

3 years ago

15

HELP WANTED with this equation!

1 answer:

dmitriy555 [2]3 years ago

3 0

Answer:

Step-by-step explanation:

5/8 = 15/24 times 4 2.5 an hour

2/3 = 16/24 times 5 3 an hour

Machine B has the greater rate

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the decimals are 0.32 and 1.29

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9. A carpenter bought 4 rolls of electric wire. He got 60.24 meters of

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the answer is 64.24 meter

Step-by-step explanation:

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2 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

3 years ago

What is the equation of the line that goes through the point (6,-1) and is parallel to the line represented by the equation belo

stepladder [879]

$\huge{\boxed{y=-\frac{5}{6} x+4}}$

Parallel lines share the same slope, so the slope of the parallel line in this case must be $-\frac{5}{6}$ .

Point-slope form is $y-y_1=m(x-x_1)$ , where $m$ is the slope and $(x_1, y_1)$ is any known point on the line.

Plug in the values. $y-(-1)=-\frac{5}{6} (x-6)$

Simplify and distribute. $y+1=-\frac{5}{6} x+5$

Subtract 1 from both sides. $\boxed{y=-\frac{5}{6} x+4}$

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