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Masja [62]
3 years ago
10

What would be the resulting molaritybof a solution made by dissolving 17.8 g of LiF in enough water to make a 915-millimeter sol

ution?
Chemistry
2 answers:
Sati [7]3 years ago
6 0
<span>Answer: <u>Molarity of solution is 0.751 M. </u>

Reason:
Given: weight of solute (LiF) = 17.8 g, volume of solution = 915 ml = 0.915 l

We know that,
Molarity = </span>\frac{\text{weight of solute (g)}}{\text{Molecular weight X Volume of solution(l)}}<span>

<em>Molecular Weight of LiF = 25.9 g/mol. </em>

</span>∴<span>, Molarity = </span>\frac{17.8}{25.9X0.915}
<span>                 = 0.751 M</span>
EleoNora [17]3 years ago
5 0

Answer:

0.751 M

Explanation:

Given:

Mass of LiF (solute), m = 17.8 g

Volume of water (solvent), V = 915 ml = 0.915 L

Formula:

Molar mass of LiF = 25.9 g/mol

Molarity = \frac{moles of solute}{Volume of solution}

Moles LiF= \frac{Mass}{Molar Mass} = \frac{17.8 g}{25.9 g/mol} = 0.6873 moles

Molarity = \frac{0.6873 moles}{0.915 L} = 0.751 moles/L

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Yesterday we combined Hydrochloric Acid HCl with Sodium Hydroxide NaOH in a violent reaction that resulted in water H2O and comm
IceJOKER [234]
Reaction:
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</span><span>1 mole of HCl = 36,5 g
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</span><span>so, according to the reaction:
</span><span>1 mol HCl = 1 mol NaOH
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</span><u>
answer: 36,5 g HCl (hydrochloric acid)
</u><span> ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
</span><span>next question.
</span><span>
1 mole of NaCl = 58,5 g
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</span>
so, according to the reaction:
1 mole of HCl (36,5 g) <span>----------------- - 1 mole of NaCl (58,5 g)
</span><span>(the same for NaOH)
i
</span>1 mole of HCl<span> (36,5 g) ------------------ 1 mole of H2O (18 g)
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7 0
3 years ago
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defon

Newton first law of motion

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