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Juliette [100K]

3 years ago

13

What happens to the density of ocean water when salinity increases? A. It increases. B. It decreases. C. It becomes variable. D.

It doesn't change.

1 answer:

omeli [17]3 years ago

3 0

A. It increases... but slightly. Good luck!

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Help me it’s for a test I have??

Volgvan

1. C
2. A
3. E
4. D
5. B
6. F
i might have 2 and 6 mixed up, not completely sure tho

4 0

3 years ago

Read 2 more answers

The half-life of plutonium 239 is 24,200 years. Assume that the decay rate is proportional to the amount. Determine the amount o

kotykmax [81]

Answer:

time taken is equal to 14,156 years

Explanation:

we know,

$Y=Ae^{-kt}$

at t = 0

Y(0) = A

given that half life of plutonium 239 = 24,200

$\dfrac{A}{2}=Ae^{-kt}\\0.5=e^{-kt}\\k\times 24200 = ln(2)\\k = \dfrac{ ln(2)}{24200}$

$Y=Ae^{-kt}$

$\frac{3}{2} = e^{-kt}\\ln(1.5)=-\dfrac{ ln(2)}{24200}\times t\\t=-\dfrac{ln(1.5)\times 24200}{ ln(2)}\\t=14,156 \ years$

hence time taken is equal to 14,156 years

5 0

3 years ago

El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es

topjm [15]

Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

P₁ = P₂

pressure is defined by

P = F / A

we subtitute

F₁ / A₁ = F₂ / A₂

F₁ = F₂ A₁ / A₂

the area in a circle is

A = π r² = π d² / 4

we substitute

F₁ = F₂ (d₁ / d₂)²

we calculate

F₁ = 17640 (2/32)²

F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

P₁ = F₁ / A₁

P₁ = F₁ 4 / π d₁²

let's calculate

P₁ = 68.9 4 / (π 0.02²)

P₁ = 219.3 Pa

3 0

3 years ago

Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so

lisabon 2012 [21]

As per kinematics equation we are given that

$v^2 = v_o^2 + 2ax$

now we are given that

a = 2.55 m/s^2

$v_0 = 21.8 m/s$

$v = 0$

now we need to find x

from above equation we have

$0^2 = 21.8^2 + 2(2.55)x$

$0 = 475.24 + 5.1 x$

$x = 93.2 m$

so it will cover a distance of 93.2 m

7 0

3 years ago

Read 2 more answers

As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3

german

As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
seconds. Calculate the acceleration of the horse.
Can anybody help ?

8 0

3 years ago