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ANTONII [103]
3 years ago
12

Which statement about polymers is true?

Physics
1 answer:
Mamont248 [21]3 years ago
6 0
Where are the statements? You forgot to attach them lol
You might be interested in
A car (m = 1302 kg) traveling along a road begins accelerating with a constant acceleration of 1.50 m/s2 in the direction of mot
antiseptic1488 [7]

First we will use the concepts of motion kinetics for which the final speed is defined as shown below,

v_f^2=v_i^2+2as

Here,

v_f= Final velocity

v_i= Initial velocity

a = Acceleration

s = Distance

Replacing,

(35)^2 = v_i^2+2(1.5)(392)

v_i = 7m/s

Using the conservation of energy for kinetic energy we have,

KE = \frac{1}{2}mv_i^2

KE = \frac{1}{2}(1302)(7)^2

KE = 31900J

Therefore the kinetic energy of the car is 31900J

5 0
4 years ago
Need help with question 1) and 2) please ASAP ??? 15 points ?
Vaselesa [24]
1- interaction between 2 objects
2- action- reaction force pairs
3 0
3 years ago
A 6 kilogram block in outer space is moving at -100 m/s (to the left). It suddenly experiences three forces as shown below (in t
Blizzard [7]

Answer:

x = 1474.9 [m]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

We must understand that when forces are applied on the body, they tend to slow the body down to stop it.

So as the body continues to move to the left, it is slowing down. Therefore we must calculate this deceleration value using Newton's second law. We must perform a sum of forces on the x-axis equal to the product of mass by acceleration. With leftward movement as negative and rightward forces as positive.

ΣF = m*a

10 +12*sin(60)= - 6*a\\a = - 3.39[m/s^{2}]

Now using the following equation of kinematics, we can calculate the distance of the block, before stopping completely. The initial speed must be 100 [m/s].

v_{f}^{2} =v_{o}^{2}-2*a*x

where:

Vf = final velocity = 0 (the block stops)

Vo = initial velocity = 100 [m/s]

a = - 3.39 [m/s²]

x = displacement [m]

0 = 100^{2}-2*3.39*x\\x=\frac{10000}{2*3.39}\\x=1474.9[m]

4 0
3 years ago
motorcycle accelerates from rest to a final velocity of 27 m/s in 9 seconds. What is its acceleration?
Vedmedyk [2.9K]

Answer:

3 m/s squared

Explanation:

The formula you use is Vf= Vi + at. You rearrange it to a= Vf - Vi/t. The Vf is 27m/s. The Vi is 0m/s and the t is 9s. Cross out Vi since it’s zero and you’re left with a= 27m/s divided by 9s, which equals 3

5 0
3 years ago
The distance between two slits is 1.50 *10-5 m. A beam of coherent light of wavelength 600 nm illuminates these slits, and the d
Fed [463]

Answer: y = 2.4×10^-6m or y= 2.4μm

Explanation: The formulae for the distance between the central bright fringe to any other fringe in pattern is given as

y = R×mλ/d

Where y = distance between nth fringe and Central bright spot fringe.

m = position of fringe = 4

λ = wavelength of light= 600nm = 600×10^-9 m

d = distance between slits = 1.50×10^-5m

R = distance between slit and screen = 2m

y = 2 × 4 × 600×10^-9/2

y = 4800×10^-9/2

y = 2400 × 10^-9

y = 2.4×10^-6m or y= 2.4μm

8 0
3 years ago
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