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3 years ago

Which statement about polymers is true?

Physics

1 answer:

Mamont248 [21]3 years ago

6 0

Where are the statements? You forgot to attach them lol

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Find the surface area of the prism 14yd 6yd 10yd

castortr0y [4]

the answer is 568 yd^2

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4 years ago

Argon gas enters steadily an adiabatic turbine at 900 kPa and 450C with a velocity of 80 m/s and leaves at 150 kPa with a veloc

Crazy boy [7]

Answer:

Temperature at the exit = $267.3 C$

Explanation:

For the steady energy flow through a control volume, the power output is given as

$W_{out}= -m_{f}(h_{2}-h_{1} + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})$

Inlet area of the turbine = $60cm^{2}= 0.006m^{2}$

To find the mass flow rate, we can apply the ideal gas laws to estimate the specific volume, from there we can get the mass flow rate.

Assuming Argon behaves as an Ideal gas, we have the specific volume $v_{1}$

$v_{1}=\frac{RT_{1}}{P_{1}}=\frac{0.2081\times723}{900}=0.1672m^{3}/kg$

$m_{f}=\frac{1}{v_{1}}\times A_{1}V_{1} = \frac{1}{0.1672}\times(0.006)(80)=2.871kg/sec$

for Ideal gasses, the enthalpy change can be calculated using the formula

$h_{2}-h_{1}=C_{p}(T_{2}-T_{1})$

hence we have

$W_{out}= -m_{f}((C_{p}(T_{2}-T_{1}) + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})$

$250= -2.871((0.5203(T_{2}-450) + \frac{150^{2}}{2\times 1000} - \frac{80^{2}}{2\times 1000})$

<em>Note: to convert the Kinetic energy term to kilojoules, it was multiplied by 1000</em>

evaluating the above equation, we have $T_{2}=267.3C$

Hence, the temperature at the exit = $267.3 C$

5 0

3 years ago

If you could live any where except for where you are now where would you live

laila [671]

Answer:

I would live in the Atlantic ocean on a lux liner

Explanation:

4 0

3 years ago

Read 2 more answers

A car battery has a rating of 250 ampere-hours. This rating is one indication of the total charge that the battery can provide t

Serga [27]

Answer:

Total charge provided by the battery could be 900000 C.

Maximum current provided by the battery for 37 minutes could be 405.405 A

Explanation:

Rating= 250 A-h

a. Total charge:

$Rating=Q/t\\Q=Rating.t\\$

Suppose t=1h

$Q=250 A(1h)\\Q=250 A(3600 sec)\\Q= 900000 A.sec$

We konw that $Ampere=\frac{Coulomb}{sec}$ , replacing:

$Q=900000(\frac{Coulomb}{sec})(sec)\\Q=900000 Coulomb$

Total charge provided by the battery could be 900000 C.

b. Maximum current for 37 minutes

$I=\frac{Q}{t} \\I=\frac{900000 C}{37*60 sec}\\I=405.405 A$

Maximum current provided by the battery for 37 minutes could be 405.405 A

4 0

3 years ago

A circular force is applied to a

lara [203]

Explanation:

A centripetal force (from Latin centrum, "center" and petere, "to seek") is a force that makes a body follow a curved path. (not sure but hope this helps )

8 0

3 years ago

Read 2 more answers