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r-ruslan [8.4K]
3 years ago
14

Feng and Isaac are riding on a merry-go- round. Feng rides on a horse at the outer rim of the circular platform, twice as far fr

om the center of the circular platform as Isaac, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, what is Feng’s angular speed?
1. impossible to determine
2. half of Isaac’s
3. the same as Isaac’s
4. twice Isaac’s
Physics
1 answer:
frez [133]3 years ago
3 0

Answer:

Option 3

Explanation:

Two rims of the merry go round must move with the same angular speed. If they move with different angular speed, the two rims will move away from each other and must get separated after certain period of time. But since the two rims are rotating together without separation, hence they must be having same angular speed. In this question the angular speed of Freng’s must be equal to the angular speed of Isaac.

Hence, option 3 is correct

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Answer:

    IMA of given system =   \frac{F_{r} }{F_{e} }

Explanation:

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                                                IMA =   \frac{F_{r} }{F_{e} }

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Explanation:

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