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r-ruslan [8.4K]
3 years ago
14

Feng and Isaac are riding on a merry-go- round. Feng rides on a horse at the outer rim of the circular platform, twice as far fr

om the center of the circular platform as Isaac, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, what is Feng’s angular speed?
1. impossible to determine
2. half of Isaac’s
3. the same as Isaac’s
4. twice Isaac’s
Physics
1 answer:
frez [133]3 years ago
3 0

Answer:

Option 3

Explanation:

Two rims of the merry go round must move with the same angular speed. If they move with different angular speed, the two rims will move away from each other and must get separated after certain period of time. But since the two rims are rotating together without separation, hence they must be having same angular speed. In this question the angular speed of Freng’s must be equal to the angular speed of Isaac.

Hence, option 3 is correct

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A 4.0-m-diameter playground merry-go-round, with a moment of inertia of
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Answer:

7.1 ms⁻¹

Explanation:

d = diameter of merry-go-round = 4 m

r = radius of merry-go-round = \frac{d}{2} =  \frac{4}{2} = 2 m

I = moment of inertia = 500 kgm²

w_{i} = angular velocity of merry-go-round before ryan jumps = 2.0 rad/s

w_{f} = angular velocity of merry-go-round after ryan jumps = 0 rad/s

v = velocity of ryan before jumping onto the merry-go-round

m = mass of ryan = 70 kg

Using conservation of angular momentum

Iw_{i} - m v r = (I + mr^{2})w_{f}

(500)(2.0) - (70) v (2) = (I + mr^{2})(0)

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v = 7.1 ms⁻¹

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How much work is done if a force of 20 N moves an object a distance of 6 m?​
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Explanation:

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The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th
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Answer:

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Here we have

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Substituting

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