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2 years ago

A square has an area of 49 cm2. what is the length of each side?

Mathematics

1 answer:

Deffense [45]2 years ago

3 0

Answer: 24.5

Step-by-step explanation:

You might be interested in

Factorize 9(a+1)^2-81

lora16 [44]

Answer:

The answer is 9(a-2)(a+4).

Step-by-step explanation:

Use $a^{2} -b^{2} =(a-b)(a+b)$

$9(a+1)^{2} -81= 9( (a+1)^{2}-9)= 9( (a+1)^{2}-3^{2} )= 9(a+1-3)(a+1+3)\\=9(a-2)(a+4).$

6 0

2 years ago

a gardener has 322 tulip bulbs she wants to plant rows of 15 bulbs how many bulbs can be planted how many bulbs will she have le

Elden [556K]

Answer:315 bulbs planted and 7 left over

Step-by-step explanation:322/15 = 21.44

Roughly around 21 rows.

21 x 15 = 315 bulbs planted

322 - 315 = 7 bulbs left over

3 0

2 years ago

Jeremy’s pay started at a $500 per week. Every year his pay will increase by $25 per week. Write an equation that models his wee

algol [13]

Answer:

W = 500 + 25x

Step-by-step explanation:

Jeremy’s pay started at $500 per week. Every year his pay will increase by $25 per week.

Now, after x years his pay per week will increase by $(25x).

Therefore, if we model the weekly payment of Jeremy by an equation, then it will be given by

W = 500 + 25x

where W is his weekly payment after x years. (Answer)

8 0

2 years ago

Help I cannot figure this question out.

netineya [11]

Answer:

B. x = -1 ± i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² + 2x = -2

Step 2: Identify Variables

Rewrite Quadratic in Standard Form [Addition Property of Equality]: x² + 2x + 2 = 0
Break up Quadratic: a = 1, b = 2, c = 2

Step 3: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-2 \pm \sqrt{2^2-4(1)(2)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-2 \pm \sqrt{4-4(1)(2)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-2 \pm \sqrt{4-8}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-2 \pm \sqrt{-4}}{2}$
[√Radical] Factor: $\displaystyle x=\frac{-2 \pm \sqrt{-1}\sqrt{4}}{2}$
[√Radicals] Simplify: $\displaystyle x=\frac{-2 \pm 2i}{2}$
Factor: $\displaystyle x=\frac{2(-1 \pm i)}{2}$
Divide: $\displaystyle x = -1 \pm i$