Answer:
3.0 mol H₂O
Explanation:
Step 1: Write the balanced combustion equation
C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O
Step 2: Establish the appropriate molar ratio
The molar ratio of C₂H₆ to H₂O is 1:3.
Step 3: Calculate the moles of H₂O formed from 1.0 mole of C₂H₆
1.0 mol C₂H₆ × 3 mol H₂O/1 mol C₂H₆ = 3.0 mol H₂O
Energy required to raise the temperature from 35°C - 45 °C= 25116 J.
specific heat, the quantity of warmth required to raise the temperature of one gram of a substance by means of one Celsius degree. The units of precise warmth are generally energy or joules consistent with gram according to Celsius diploma. for instance, the unique warmth of water is 1 calorie (or 4.186 joules) according to gram in step with Celsius degree.
solving,
Sample of liquid = 400. 0 g
temperature = 30. 0 ºc
joules of energy are required to raise the temperature of the water to 45. 0 ºc
therefore rise in temperature 45 - 30 = 15°C
Specific heat capacity = 4.186 J/g m °C
In kelvin = 273 + 15 = 288
= ∴ energy required = Q = m s ( t final - t initial)
= 400*4.186 * 15
= 25116 joule
Learn more about specific heat here:-brainly.com/question/21406849
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