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2 years ago

1 mole of a gas occupies 22.4 L at ________

1 answer:

8 0

Answer: At STP, one mole (6.02 × 1023 representative particles) of any gas occupies a volume of 22.4 L (Figure below). A mole of any gas occupies 22.4 L at standard temperature and pressure (0°C and 1 atm).

Explanation:

That the answer

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Will hydrogen ever make a double bond?

Andrei [34K]

No, hydrogen can only hold one bond and that's it. It only needs to be paired with one bond.

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2 years ago

Read 2 more answers

How many liters are in a .00813M solution that contains 1.55 g of KBr?

Sloan [31]

Answer:

1.602 L (or) 1602 mL

Explanation:

Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,

Molarity = Moles / Volume of Solution ----- (1)

Rearranging above equation for volume,

Volume of solution = Moles / Molarity -------(2)

Data Given;

Molarity = 0.00813 mol.L⁻¹

Mass = 1.55 g

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 1.55 g / 119.002 g.mol⁻¹

Moles = 0.0130 mol

Now, putting value of Moles and Molarity in eq. 2,

Volume of solution = 0.0130 mol / 0.00813 mol.L⁻¹

Volume of solution = 1.60 L

or,

Volume of solution = 1602 mL

5 0

2 years ago

Zinc sulfate is a 2-ion electrolyte,

Gekata [30.6K]

Answer: The value of i is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

Explanation:

The equation used to calculate the Vant' Hoff factor in dissociation follows:

$\alpha =\frac{i-1}{n-1}$

where,

$\alpha$ = degree of dissociation = 40% = 0.40

i = Vant' Hoff factor

n = number of ions dissociated = 2

Putting values in above equation, we get:

$0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4$

The equation used to calculate the degee of dissociation follows:

$\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}$

Total number of particles taken = 100

Degree of dissociation = 40% = 0.40

Putting values in above equation, we get:

$0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40$

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

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2 years ago

How does a buffer resist change in ph upon addition of a strong acid?

lora16 [44]

Any buffer exists in this equilibrium

HA <=> $H^+ + A^-$
In a buffer, there is a large reservoir of both the undissociated acid (HA) and its conjugate base ( $A^-$ )

When a strong acid is added, it reacts with the large reservoir of the conjugate base ( $A^-$ ) forming a salt and water. Since this large reservoir of the conjugate base is used, the ph does not alter drastically, but instead resist the pH change.

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3 years ago

True or false a solid has a constant shape and volume

dusya [7]

The answer you are looking for is True

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2 years ago