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sergij07 [2.7K]
3 years ago
10

1 mole of a gas occupies 22.4 L at ________

Chemistry
1 answer:
artcher [175]3 years ago
8 0

Answer: At STP, one mole (6.02 × 1023 representative particles) of any gas occupies a volume of 22.4 L (Figure below). A mole of any gas occupies 22.4 L at standard temperature and pressure (0°C and 1 atm).

Explanation:

That the answer

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3 years ago
Define law of conservation of mass
horrorfan [7]

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction. Hope this helps!


7 0
3 years ago
What is the approximate bond angle around the central carbon atom in acrolein?
Soloha48 [4]

Answer:

The approximate bond angle around the central carbon atom in acrolein is 120°.

Explanation:

The structure of acrolein is shown in the attachment. From the structure, we can deduce that the central carbon atom is in an sp2 hybridization (Atoms with a double bond hybridize in an sp2 fashion).

Atoms with sp2 hybridization have trigonal planar geometry, in this kind of hybridization, bonds are oriented the farthest away possible from each other, to minimize overlapping and the angle that allows that is 120°. 

7 0
3 years ago
What kind of sport do you have interest the most and explain why? <br>​
lidiya [134]

Answer

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Explanation:

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7 0
2 years ago
A 75.0 g sample of dinitrogen monoxide is confined in a 3.q L vessel. What is the pressure( in atm) at 115 celsius
Nonamiya [84]
Data Given:
                  Pressure  =  P  =  ?

                  Volume  =  V  =  3.0 L

                  Temperature  =  T  =  115 °C + 273  =  388 K

                  Mass  =  m  =  75.0 g

                  M.mass  =  M  =  44 g/mol

Solution:
              Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
                                      P V  =  n R T
Solving for P,
                                      P  =  n R T / V      ------ (1)
Calculating Moles,
                                      n  =  m / M

                                      n  =  75.0 g / 44 g.mol⁻¹

                                      n  =  1.704 mol

Putting Values in Eq. 1,

                    P  =  (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L

                    P  =  18.08 atm
7 0
3 years ago
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