Suppose that three numbers are selected one by one, at random, and without replacement, from the set of integers {1, 2, 3, . . .
, n}. what is the probability that the third number falls between the first two if the first number is smaller than the second?
1 answer:
A - the third number falls between the first two
B - the first number is smaller than the second

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Y=-2/81x^2+50 is the answer
<span>2 3/4 = 2.75
so
</span>2 3/4 = 2.75%
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yes
Step-by-step explanation:
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A. 8
Step-by-step explanation:
sqrt{64} is 8 (8*8)
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3 1/6
Step-by-step explanation:
19/6= 3.1666666666666 also known as 3 1/6
check your work by multiplying 3 1/6 by 6 and get 19