Explanation:
Given parameters:
Mass of sample = 235g
Molecular mass of sample = 128.1g
Empirical formula = CH₂O
Unknown:
Mass of each element in the sample = ?
Solution:
To solve this problem, we must know that the empirical formula of any compound is the simplest ratio of the atoms it contains. This is not the true formula of the compound.
Molecular formula = (Empirical formula)ₙ
Let us find the molecular mass of the sample;
CH₂O = 12 + 2(1) + 16 = 30g
128.1 = (30)n
n = 4
The molecular formula of the compound is; (CH₂O)₄ = C₄H₈O₄
Now to find the grams of each element in the sample;
Express the molecular mass of each element and that of the compound as a fraction and multiply with the given mass;
For C;
= 88.06g
H; 
= 14.68g
O: 
= 117.41g
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Mass composition brainly.com/question/3018544
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(CH3)3N + H2O ---> (CH3)3NH+ + OH-
The equation of Kb:
Kb = [(CH3)3NH+][OH-]/[(CH3)3N]
<h3>
What do we know about the process of dissolution?</h3>
A solute can dissolve in a solvent in a solid, liquid, or gaseous phase to create a solution through the process of dissolution. Solubility. The greatest amount of a solute that may dissolve in a solvent at a particular temperature is known as its solubility. The solution is said to as saturated when the maximum amount of solute is present.
Several variables influence solubility, including:
- The solute's concentration
- The system's temperature
- Pressure (for gases in solution)
- The solvent's and solute's polarity
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C. single replacement. A single replacement is represented by this formula : AB + C = AC + B
Crystals of phthalic acid can be grown twice as fast compared to the smaller crystals
The activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.
<h3>What is used in comparing reactivity of metals?</h3>
The reactivity of metals can be compared using their electrode potentials which is a measures of the ability of the metal to donate electrons to another metal.
When comparing the reactivity of metals, the metal with the lesser negative electrode potential will be more reactive than another with a greater negative or positive electrode potential.
Therefore, the activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.
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