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Kaylis [27]
3 years ago
7

The type of reaction that takes place when one element reacts with a compound to form a new compound and a different element is

a ____
a. combination reaction.
b. decomposition reaction.
c. single-replacement reaction.
d. double-replacement reaction.
Chemistry
2 answers:
Tems11 [23]3 years ago
7 0

Answer: c. single-replacement reaction.

Explanation:

Combination is a chemical reaction in which two or more than two substances combine to form a single product.

A+B\rightarrow AB

Decomposition is a chemical reaction in which one substance decompose to form two or more than two products.

AB\rightarrow A+B

A single replacement  is a chemical reaction in which a more reactive element displaces a less reactive element from its salt solution, thus one element reacts with a compound to form a new compound and a different element.

A+BC\rightarrow B+AC

Double displacement is a chemical reaction in which ion exchange takes place.

AB+CD\rightarrow AD+BC

Airida [17]3 years ago
4 0
C. single replacement. A single replacement is represented by this formula : AB + C = AC + B
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<h3>Answer:</h3>

             7.57 × 10⁻²² g of F

<h3>Solution:</h3>

Data Given:

                 Number of Molecules  =  8

                 M.Mass of BF₃ =  67.82 g.mol⁻¹

                 Mass of Fluorine atoms  =  ?

Step 1: Calculate Moles of BF₃

           Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Putting value,

            Moles  =   8 Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

            Moles  =  1.33 × 10⁻²³ mol

Step 2: Calculate Mass of BF₃:

                   Moles  =  Mass ÷ M.Mass

Solving for Mass,

                   Mass  =  Moles × M.Mass

Putting values,

                   Mass  =  1.33 × 10⁻²³ mol × 67.82 g.mol⁻¹

                   Mass  =  9.0 × 10⁻²² g

Step 3: Calculate Mass of Fluorine Atoms:

As,

                         67.82 g BF₃ contains  =  57 g of F

So,

                    9.0 × 10⁻²² g will contain  =  X g of F

Solving for X,

                       X =  (9.0 × 10⁻²² g × 57 g) ÷ 67.82 g

                        X  =  7.57 × 10⁻²² g of F

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Answer:

The mass of 0.280 mole sample of sodium hydroxide NaOH​ is 11.2 grams.

Explanation:

To know the mass in grams of 0.280 moles of sample of sodium hydroxide NaOH, you must know the molar mass of the compound, that is, the mass of one mole of a substance, which can be an element or a compound.

So you know:

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So, the molar mass of NaOH is:

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Then the following rule of three can be applied: if in 1 mole of sodium hydroxide there are 40 grams, in 0.280 moles how much mass is there?

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<u><em>The mass of 0.280 mole sample of sodium hydroxide NaOH​ is 11.2 grams.</em></u>

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Thus, we can write a more simplify illustration for the model above as

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