What is the displacement of the student from the bus stop to the mailbox?

An object has a mass of 13.5 kilograms. What force is required to accelerate it to a rate of 9.5 m/s2?

Zigmanuir [339]

Force can be expressed as the product of mass and acceleration. Mathematically, that's F = m(a). Plugging the given into the equation, we have F = (13.5 kg)(9.5 m/s²) = 128.3 kg.m/s² or 128.3 N<span>. </span>

4 0

3 years ago

Prove for N/C=Volt/m

Zigmanuir [339]

Answer:

simple, Volt =change in potential energy/Charge

the unit of energy is newton meter (Force*distance)

the unit of charge is coloumb

So, Volt/meter=newton* meter/coloumb*meter

=newton/coloumb (hence proved)

This unit is the potential drop per unit of length in a conductive wire with uniform resistance

7 0

3 years ago

One of the frequencies used to transmit and receive cellular telephone signals in the United States is 985 MHz. What is the wave

tia_tia [17]

Answer:

approximately 304358

Explanation:

wavelength = speed / frequency

speed of an electromagnetic wave is 299,792,458 m/s in a vacuum

5 0

2 years ago

An octopus propels itself through the water by ejecting water through a funnel in its body. How does this demonstrate Newton’s t

valina [46]

Answer: The answer would be C. When Octopus eject the water out, the water acts with an equal force on the octopus in opposite direction.

Explanation:

An octopus propels itself forward in the water by ejecting water backward through a funnel in its body.

Hope this helps! :D

8 0

2 years ago

Read 2 more answers

To what tension (in newtons) must you adjust the screw so that a transverse wave of wavelength 3.33 cm makes 621 vibrations per

PilotLPTM [1.2K]

Answer:

T=9.4 N

Explanation:

We are given that

Mass of wire,m=16.5 g= $\frac{16.5}{1000}$ kg

1 kg=1000g

Length of wire,l=75 cm= $75\times 10^{-2}$ m

1 m=100 cm

Wavelength of transverse wave= $\lambda=3.33 cm=3.33\times 10^{-2}$ m

Frequency= $621 Hz$

Mass per unit length= $m_l=\frac{m}{l}=\frac{16.5}{1000\times 75\times 10^{-2}}=0.022 kg/m$

$\nu=\frac{v}{\lambda}$

$v=\nu \lambda$

Where $\nu=$ frequency of wave

$\lambda$ =Wavelength of wave

Speed of wave=v

Using the formula

$v=3.33\times 10^{-2}\times 621=20.7m/s$

$v=\sqrt{\frac{T}{m_l}}$

$v^2=\frac{T}{m_l}$

$T=v^2m_l$

Using the formula

$T=(20.7)^2\times 0.022=9.4N$

Hence, the tension,T=9.4 N

7 0

3 years ago