All categories

3 years ago

What amount of force is needed to propel and object of 27 kg to an acceleration of 11,550 m/s^2? (1 point)

Physics

1 answer:

aliya0001 [1]3 years ago

3 0

Answer:

311,850 N

Explanation:

We can solve the problem by using Newton's second law:

$F=ma$

where

F is the net force applied on an object

m is the mass of the object

a is its acceleration

For the object in this problem,

m = 27 kg

$a=11550 m/s^2$

Substituting, we find the force required:

$F=(27)(11550)=311,850 N$

You might be interested in

An object is dropped from a 32 m tall building. How fast will it be going when it strikes the ground?

Phantasy [73]

Velocity should be 25.3m/s

3 0

3 years ago

A car accelerates from 6.0 m/s to 18 m/s at a rate of 3.0 m/s2. How far does it travel while accelerating

AlekseyPX

Answer:

48m, hope this helps :)

4 0

4 years ago

A racquet ball with mass m = 0.256 kg is moving toward the wall at v = 11.8 m/s and at an angle of θ = 29° with respect to the h

icang [17]

Answer:

Part a)

$P = 5.72 kg m/s$

Part b)

$\Delta P = 2.93 kg m/s$

Part c)

$F = 44.4 N$

Part d)

$\Delta P = 5.02 kg m/s$

Part e)

$\Delta t = 0.113 s$

Part f)

$\Delta K = 0$

Explanation:

As we know that initial velocity of the ball is given as

$v = 11.8 cos29 \hat i + 11.8 sin29 \hat j$

$v_i = 10.3 \hat i + 5.72 \hat j$

Now final velocity of the system is given as

$v_f = 10.3\hat i - 5.72\hat j$

Part a)

now magnitude of initial momentum is given as

$P = mv$

$P = 0.256(11.8)$

$P = 5.72 kg m/s$

Part b)

Change in momentum is given as

$\Delta P = m(v_f - v_i)$

$\Delta P = 0.256(5.72 + 5.72)$

$\Delta P = 2.93 kg m/s$

Part c)

As we know that average force is defined as the rate of change in momentum

so here we have

$F = \frac{\Delta P}{\Delta t}$

$F = \frac{2.93}{0.066}$

$F = 44.4 N$

Part d)

Magnitude of change in momentum is given as

$\Delta P = m(v_f - v_i)$

$\Delta P = 0.256(7.8 + 11.8)$

$\Delta P = 5.02 kg m/s$

Part e)

As we know that in 2nd case the force is same as the initial force

so we will have

$\frac{\Delta P}{\Delta t} = F$

$\frac{5.02}{\Delta t} = 44.4$

$\Delta t = 0.113 s$

Part f)

Since this is elastic collision so change in kinetic energy must be ZERO

$\Delta K = 0$

8 0

3 years ago

Match the letter and term.

rosijanka [135]

Answer:

1. Nitrogen

2. Oxygen

3. Carbon dioxide

4. Water vapor

5. Ozone

Explanation:

The atmosphere composes of 78% nitrogen which occupies the largest percentage followed by oxygen which takes up 21%, Argon takes up 1% then other components such as water vapor occupy between 0-7% and ozone takes 0.0-0.01. Moreover, 0.01-0.1 is occupied by carbon dioxide. Therefore, the answers for 1-5 are as follows.

1. Nitrogen

2. Oxygen

3. Carbon dioxide

4. Water vapor

5. Ozone

4 0

4 years ago

(Need help pls)!!!!! <br><br><br>

Rainbow [258]

Answer:

I assume they want answer A, but it's a silly question.

Explanation:

Well, if we assume that the girls are applying equal force, as they are the same size and strength (apparently also the same resolve etc.).

Equal force in opposite directions means the composite force is null. An object that no force is applied to continues moving in the same direction, so if the doll was moving somewhere, it would keep doing so, except all of this makes no sense the doll is not in gravityless vacuum what are we even talking about.

The answer A is the least ridiculous.

8 0

3 years ago