An ampere (AM-pir), or amp 
 
        
             
        
        
        
Answer:
u = 104.68 m/s
Explanation:
given,
horizontal distance = 150 m
elevation of  12.4 m
angle = 8.6°
horizontal motion = x = u cos θ. t .............(1)
vertical motion = 
................(2)
from equation(1) and (2)
..........{3}




u = 104.68 m/s
The initial speed of the ball is u = 104.68 m/s
 
        
             
        
        
        
That's called the "normal" to the surface at that point.