Answer:
The kinetic energy of the particle as it moves through point B is 7.9 J.
Explanation:
The kinetic energy of the particle is:
<u>Where</u>:
K: is the kinetic energy
: is the potential energy
q: is the particle's charge = 0.8 mC
ΔV: is the electric potential = 1.5 kV
Now, the kinetic energy of the particle as it moves through point B is:
Therefore, the kinetic energy of the particle as it moves through point B is 7.9 J.
I hope it helps you!
Answer:
F = M a where M is acceleration and a is acceleration
a = x / s^2 = distance / time squared
The Newton is derived because mass, distance, and time are all fundamental units One would have to look at the fundamental requirements for these definitions, but they can all be repeated in a laboratory.
So the Newton is determined from these fundamental units and since the Joule equals Newton * Distance it is also derived from the fundamental units.
If one has the three fundamental units then one can derive the Joule and Newton.
Answer:
F = - 3.56*10⁵ N
Explanation:
To attempt this question, we use the formula for the relationship between momentum and the amount of movement.
I = F t = Δp
Next, we try to find the time that the average speed in the contact is constant (v = 600m / s), so we say
v = d / t
t = d / v
Given that
m = 26 g = 26 10⁻³ kg
d = 50 mm = 50 10⁻³ m
t = d/v
t = 50 10⁻³ / 600
t = 8.33 10⁻⁵ s
F t = m v - m v₀
This is so, because the bullet bounces the speed sign after the crash is negative
F = m (v-vo) / t
F = 26*10⁻³ (-500 - 640) / 8.33*10⁻⁵
F = - 3.56*10⁵ N
The negative sign is as a result of the force exerted against the bullet
Correct question is;
1/0.12 = (1/0.05) + (1/d')
Answer:
d' = -1/700
Explanation:
1/0.12 = (1/0.05) + (1/d')
Let's rearrange to get;
(1/d') = (1/0.12) - (1/0.05)
(1/d') = (1/(12/100)) - (1/(5/100))
(1/d') = 100/12 - 100/5
Let's multiply through by 60 to get rid of the denominators on the right side;
> (1/d') = 500 - 1200
> (1/d') = -700
> d' = -1/700
El beneficio que obtuvo es de 2 L
