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Umnica [9.8K]
3 years ago
14

What is the independent variable in the graph?

Physics
1 answer:
baherus [9]3 years ago
8 0
The independent variable is the time (minutes). The temperature is the dependent variable. 
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An embolus can cause which of the following?
QveST [7]
I think it’s C. Stroke if not then D
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You drop a pencil from your desk, which is 1 meter above the floor. How long does it take for the pencil to hit the floor? How f
vova2212 [387]

Answer:

1. 0.45 s.

2. 4.41 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) = 1 m

Time (t) =?

Velocity (v) =?

1. Determination of the time taken for the pencil to hit the floor.

Height (h) = 1 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

1 = ½ × 9.8 × t²

1 = 4.9 × t²

Divide both side by 4.8

t² = 1/4.9

Take the square root of both side

t = √(1/4.9)

t = 0.45 s.

Thus, it will take 0.45 s for the pencil to hit the floor.

2. Determination of the velocity with which the pencil hit the floor.

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 0.45 s.

Final velocity (v) =?

v = u + gt

v = 0 + (9.8 × 0.45)

v = 0 + 4.41

v = 4.41 m/s

Thus, the pencil hit the floor with a velocity of 4.41 m/s

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4 years ago
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The answer is the third one down. New evidence may contradict the old evidence of a certain theory.
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What do butterflies have on their feet which allows them to sense different strengths and types of nectar?
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4 0
3 years ago
Read 2 more answers
Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings
Hatshy [7]

Answer:0.316 rad/s

Explanation:

Given

mass of Person m=65 kg

velocity of person v=3.8 m/s

diameter of turntable d=6.5 m

moment of Inertia of the table I_0=1850 kg-m^2

Moment of inertia of Person I

I=mr^2=65\times (\frac{6.5}{2})^2

I=686.56 kg-m^2

initial angular velocity \omega _1=\frac{v}{r}

\omega _1=\frac{3.8}{3.25}=1.17 rad/s

Conserving Angular momentum

I\omega _1=(I+I_0)\omega _2 , where \omega _2=final\ angular\ velocity

686.56\times 1.17=(686.56+1850)\times \omega _2

\omega _2=\frac{686.56}{2536.56}\times 1.17

\omega _2=0.316 rad/s

4 0
3 years ago
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