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Oxana [17]
3 years ago
6

If you start with 42 g of Fe-53, how much is left after 8.51 minutes? I​

Chemistry
2 answers:
lidiya [134]3 years ago
5 0

Answer:

2.58 good luck with everything

Paladinen [302]3 years ago
4 0

Answer:

2:38

Explanation:

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Which of the following is an example of electrical energy being converted to chemical energy?
marishachu [46]

The correct answer is option D, that is, a storage battery is charged using an electric current.  

The transformation of one form of energy into another, generally to transform the energy into more useful kind is known as energy conversion. The energy can neither be created nor be destroyed, it can only be transformed. The different forms of energy comprise light, heat, mechanical, electrical, sound, nuclear, and sound.  

In the given question, the charging of a storage battery using electric current is an example of electrical energy being converted into chemical energy.  


5 0
3 years ago
Read 2 more answers
C(s) + S8(s) → CS2(l)
Vanyuwa [196]
The balanced chemical reaction is written as:

<span>4C(s) + S8(s) → 4CS2(l)

We are given the amount of carbon and sulfur to be used in the reaction. We need to determine first the limiting reactant to be able to solve this correctly.

</span>7.70 g C ( 1 mol / 12.01 g) =0.64 mol C
19.7 g S8 ( 1 mol / 256.48 g) = 0.08 mol S8

The limiting reactant would be S8. We use this amount to calculate.

0.08 mol S8 ( 4 mol CS2 / 1 mol S8 ) ( 256.48 g / 1 mol ) = 78.8 g CS2
4 0
3 years ago
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×
Anuta_ua [19.1K]

Answer:

Kc=~1.49x10^3^4}

Explanation:

We have the reactions:

A: N_2_(_g_) + O_2_(_g_)  2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9

Our <u>target reaction</u> is:

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)

We have NO_(_g_) as a reactive in the target reaction and  NO_(_g_) is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

Then if we add reactions A and B we can obtain the target reaction, so:

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9

For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}

Kc=~1.49x10^+^3^4}

3 0
3 years ago
Q. What happens when (Also give chemical equations) :
Pani-rosa [81]

Answer:

the real tricky one question

Explanation:

7 0
3 years ago
What are two ways to make a saturated solution of NH3 in 100.g H20 at 60°C become unsaturated?
son4ous [18]
The two ways to make a saturated solution are 1 reducing the temperature of the solution and Adding more solute.<span> </span>
7 0
3 years ago
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