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svetoff [14.1K]
3 years ago
11

Help please i tried to do lab but i couldn’t figure it out

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
7 0
D. paper d, paper c, paper a, paper b
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According to Grahams law the rate of effusion of a gas is inversely proportional to the square root of it's molecular weight. The rate of diffusion is the measure of rate at which two gases mix. From this law we can say that for the two gases carbon monoxide and carbon dioxide, the rate of effusion of carbon monoxide is greater than that of carbon dioxide, this is because carbon monoxide is lighter (28 g) compared to carbon dioxide (44 g). 
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When sugar glucose, C6H12O6, is burned with air, carbon dioxide and water vapor are produced. Write the balanced equation and ca
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State the importance of oxygen for germination process
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3 years ago
The density of ethanol is 0.789 g/mL. Calculate the volume of 600 g of ethanol.
Anettt [7]

Answer:

The answer is

<h2>760.46 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of ethanol = 600 g

density = 0.789 g/mL

It's volume is

volume =  \frac{600}{0.789}  \\  = 760.4562737...

We have the final answer as

<h3>760.46 mL</h3>

Hope this helps you

6 0
3 years ago
g Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.71 g of ethane i
Kamila [148]

Answer:

6.05g

Explanation:

The reaction is given as;

Ethane + oxygen --> Carbon dioxide + water

2C2H6 + 7O2 --> 4CO2 + 6H2O

From the reaction above;

2 mol of ethane reacts with 7 mol of oxygen.

To proceed, we have to obtain the limiting reagent,

2,71g of ethane;

Number of moles = Mass / molar mass = 2.71 / 30 = 0.0903 mol

3.8g of oxygen;

Number of moles = Mass / molar mass = 3.8 / 16 = 0.2375 mol

If 0.0903 moles of ethane was used, it would require;

2 = 7

0.0903 = x

x = 0.31605 mol of oxygen needed

This means that oxygen is our limiting reagent.

From the reaction,

7 mol of oxygen yields 4 mol of carbon dioxide

0.2375 yields x?

7 = 4

0.2375 = x

x = 0.1357

Mass = Number of moles * Molar mass = 0.1357 * 44 = 6.05g

8 0
3 years ago
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