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laila [671]
4 years ago
5

The molar mass of HgO is 216.59 g/mol. The molar mass of O2 is 32.00 g/mol. How many moles of HgO are needed to produce 250.0 g

of O2?
Chemistry
1 answer:
Irina-Kira [14]4 years ago
6 0
A reaction in which Oxygen (O₂) is produced from Mercury Oxide (HgO) would be a decomposition reaction.
           2HgO    →    2Hg    +    O₂

If 250g of O₂ is needed to be produced,
then the moles of oxygen needed to be produced = 250g  ÷  32 g/mol
                                                                                     = 7.8125 mol

Now, the mole ratio of Oxygen to Mercury Oxide is  1  :  2
∴ if the moles of oxygen =  7.8125 mol
then the moles of mercury oxide = 7.8125 mol × 2
                                                        = 15.625 mol


Thus the number moles of HgO needed to produce 250.0 g of O₂ is 15.625 mol
 
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Give an example of an oxidisation reaction!
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4 0
4 years ago
You wish to calculate the mass of hydrogen gas that can be prepared from 4.93 g of srh2 and 4.14 g of h2o.
Ivenika [448]
The maximum amount of hydrogen gas that can be prepared is if all the hydrogen from both compounds is released.

The hydrogen in 4.94 g of SrH2 is calculated from the mass ratios between Sr and H

1) H2 in SrH2

Sr atomic mass = 87.62 g/mol

H2 molar mass = 2.02 g/mol

Mass of 1 mol of SrH2 = 87.62 g / mol + 2.02 g/mol = 89.64 g/mol

Ratio of H2 to SrH2 = 2.02 g H2 / 89.64 g SrH2

Proportion: 2.02 g H2 / 89.64 gSrH2 = x / 4.93 g SrH2

=> x = 4.93 g SrH2 * 2.02 g H2 / 89.64 g SrH2 = 0.111 g H2

2) H2 in H2O

2.02 g H2 / 18.02 g H2O * 4.14 g H2O = 0.464 g H2

3) Total mass of hydrogen = 0.111 g + 0.464 g = 0.575 g

Answer: 0.575 g
7 0
3 years ago
Help only 4 minutes left
vesna_86 [32]

Answer: the answer is d

Explanation: hurry and answer

4 0
3 years ago
Be sure to answer all parts.
Ede4ka [16]

The Ksp of the solution is 1.97 * 10^-9.

<h3>What is the pH?</h3>

The pH is defined as the hydrogen ion concentration of the solution. Now we have the pH of the solution as 10.9.

We know that;

pOH = 14 - pH

pOH = 14 - 10.9

pOH = 3.1

[OH^-] = Antilog [-3.1]

[OH^-] =7.9 * 10^-4 M

Now

Ksp = [M^2+] [2OH^-]^2

Ksp = s * (2s)^2

Ksp = 4s^3

Now s = 7.9 * 10^-4 M

Ksp = 4(7.9 * 10^-4)^3

Ksp = 1.97 * 10^-9

Learn more about Ksp:brainly.com/question/27132799

#SPJ1

7 0
2 years ago
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