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Answer:
Separation increases at all times that rock X falls because it falls with a greater speed
Explanation:
For both rocks, let initial velocity ∪=0
To find the displacement at any given time interval of Δt then
S= ∪Δt +0.5gΔt²
Since rock X is first released followed by Y, then X has a greater speed than Y therefore the distance covered by X is longer. This is because despite 0.5gΔt² being same for both rocks at any time Δt but rock X having already attained some velocity, its ∪Δt is more hence the separation S increases. Conclusively, S increases at all times that rock X falls since rock X falls with a greater velocity than rock Y
