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NISA [10]
2 years ago
14

El agua con trozos de hielo es heterogenea o homogenea

Chemistry
1 answer:
dimaraw [331]2 years ago
4 0
El agua con hielo es sistema heterogénea .
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Which of the following is an example of acceleration?
anzhelika [568]

Answer:

it's either B. or C.. hope this helps!

Explanation:

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2 years ago
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Acetylene gas (ethyne; HC = CH) burns in an oxyacetylene torch to produce carbon dioxide and water vapor. The heat of reaction f
Yanka [14]

The mass of CO2 produced by 26g of acetylene is 88g.

Given ,

In an oxyacetylene torch, acetylene gas (ethyne; HCCH) burns to produce carbon dioxide and water vapour.

The acetylene combustion reaction is given by,

H2O + HCCH + 5/2 O=O 2CO2

Heat of reaction for acetylene combustion = 1259kj/mol

CO2 has a molecular mass of 44g/mol.

2 moles of CO2 have a molecular mass of 88g.

On combustion, 1 mole of acetylene yields 2 moles of CO2.

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As a result, the mass of carbon dioxide produced by 26g of acetylene is 88g.

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6 0
1 year ago
1. Sodium hydroxide reacts with carbon dioxide according to the equation: 2NaOH(s) + CO2(g) →
Leno4ka [110]

The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

<h3>What is Limiting reagent ?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

Given chemical equation in balanced form ;

2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).

According to the Chemical equation ;

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    If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.

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  • 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react

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5 0
1 year ago
For the reaction represented by the equation 
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STatiana [176]

Answer:

8.00 moles.

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The ratio of Fe to FeO  is 2:2 = 1:1,  so 8 moles are produced.

8 0
3 years ago
A researcher wants to test the solubility (property of being dissolved) of salt in water as the temperature of the water increas
aev [14]
Have about 5 beakers all with different temperatures of water. Put in a teaspoon of salt at a time and when it stops dissolving stop adding and record how much salt it took. It should be more salt as the temperature rises. The independent variable is the waters temperature. The dependent variable is how much salt is used. Make sure that there is the same amount of water in each beaker. Or else it won’t work.
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