I’m sorry i’m not smart lol , i’m tryna post a question on my profile and i need to answer a question
The answer is 975S because u add all ofthem
Answer:
Explanation:
HA(aq)+H2O(l)⟺H3O+(aq)+A−(aq)(1)
you need to solve for the Ka value. To do that you use
Ka=[H3O+][A−][HA](2)
Another necessary value is the pKa value, and that is obtained through pKa=−logKa
The procedure is very similar for weak bases. The general equation of a weak base is
BOH⟺B++OH−(3)
Solving for the Kbvalue is the same as the Ka value. You use the formula
Kb=[B+][OH−][BOH](4)
The pKb value is found through pKb=−logKb
The Kw value is found withKw=[H3O+][OH−].
Kw=1.0×10−14(5)
The concentration of ClO₂⁻ at equilibrium if the initial concentration of HClO₂ is 0.0654.
<h3>What is concentration?</h3>
The concentration of any substance is the quantity of that substance in per square of the space or container.
The reaction is
HClO₂ + H₂O <=> H₃O⁺ + ClO₂⁻
The pH is 0.454 M
Ka = [H₃O⁺][ClO₂⁻ ] / [HClO₂]
2. 25 × 10⁻² m = [x][x] / 0.454-x]
2 + 0.011 - 0.004994 = 0
solve the quadratic equation
x = 0.0654 = [H3O+] = [ClO2-]
pH = -log (H3O+)
pH = -log(0.0654)
pH = 1.2
equilibrium concentrations of
[HClO2] = 0.454 -x = 0.454 -0.0654 = 0.3886 M
[ClO2- ] = x = 0.0654
Thus, the equilibrium concentrations is 0.0654.
To learn more about concentration, refer to the link:
brainly.com/question/16645766
#SPJ4