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Anni [7]
2 years ago
5

A chemistry student pours some liquid Mercury into and partially fills a graduated cylinder. She then adds liquid broming until

the meniscus of the bromine reads 100 mL. She then determines the mass of the contents excluding the graduated cylinder to be 650.1 g. How many milliliters of Mercury and how many milliliters of bromine were placed into the graduated cylinder? The density of Mercury is 13.5 g/mL and the density of bromine is 3.10 g/mL.
Chemistry
1 answer:
Dmitry_Shevchenko [17]2 years ago
4 0
Omg I ain’t readying all that my head already hurts
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Given: g on moon = –1.63 meters/second2
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What is homologous series . Write it's characteristics
Anni [7]

Answer:

Homologous series is defined as a systematic order of structurally similar organic compound containing same functional group in their family and two adjacent members differ in their molecular formula by -CH2 unit.

Characteristics:

1.Various members of homologous series contain same functional group.

2.Various members of homologous series can be represented by common formula.

3. All members of a homologous series have almost similar chemical properties.

4. All members have common method of preparation.

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2 years ago
Which of these is not an example of a molecule?
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5 0
3 years ago
How many grams of dry nh4cl need to be added to 2.50 l of a 0.800 m solution of ammonia, nh3, to prepare a buffer solution that
tia_tia [17]

Answer:

The correct answer is 574.59 grams.

Explanation:

Based on the given information, the number of moles of NH₃ will be,  

= 2.50 L × 0.800 mol/L

= 2 mol

The given pH of a buffer is 8.53

pH + pOH = 14.00

pOH = 14.00 - pH

pOH = 14.00 - 8.53

pOH = 5.47

The Kb of ammonia given is 1.8 * 10^-5. Now pKb = -logKb,  

= -log (1.8 ×10⁻⁵)

= 5.00 - log 1.8

= 5.00 - 0.26

= 4.74

Based on Henderson equation:  

pOH = pKb + log ([salt]/[base])

pOH = pKb + [NH₄⁺]/[NH₃]

5.47 = 4.74 + log ([NH₄⁺]/[NH₃])

log([NH₄⁺]/[NH₃]) = 5.47-4.74 = 0.73

[NH₄⁺]/[NH₃] = 10^0.73= 5.37

[NH₄⁺ = 5.37 × 2 mol = 10.74 mol

Now the mass of dry ammonium chloride required is,  

mass of NH₄Cl = 10.74 mol × 53.5 g/mol

= 574.59 grams.  

8 0
3 years ago
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