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solniwko [45]
3 years ago
7

The famous black planet, haunch, has a radius of 106 m, a gravitational acceleration at the surface of 4 m/s2 , and the tangenti

al speed of any point on its equator is 103 m/s. a famous haunch ant has a mass of 40 kg and is standing on a spring scale at the equator. what is the reading of the spring scale?
Physics
1 answer:
levacccp [35]3 years ago
6 0
Gravity on the surface = 4 m/s^2
Now, the acceleration due to centripetal motion, a = v^2/R

Where,
v= 10^3 m/s, R = 10^6 m
Then,
a = (10^3)^2/(10^6) = 1 m^2/s

The net gravitational acceleration = 4-1 = 3 m/s^2

The reading on the spring scale = ma = 40*3 = 120 N
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A collection of 1.25×1019 electrons has the charge <br> -3c, <br> -1c, <br> -2c
djverab [1.8K]

Answer:

-2 C

Explanation:

charge of an electron = -1.6x10^{-19}C

therefore charge of 1.25 x 10^{19} electrons = (1.6x10^{-19}) x (-1.25x10^{19}) = -2 C

3 0
3 years ago
The mass of the earth is 5.96/10kg^24. The radius of the earth is approximately 6.37x10^6 calculate the force of gravity
n200080 [17]
<h2>Answer:g=9.79ms^{-2},A object of mass m at the surface of earth experiences a force mg</h2>

Explanation:

Let M be the mass of earth.

Let R be the radius of earth.

Let G be the universal gravitational constant.

Given,

M=5.96\times 10^{24}Kg

R=6.37\times 10^{6}m

G=6.67259 \times 10^{-11}Nm^{2}Kg^{-2}

Let g be the acceleration due to gravity.

Then,g=\dfrac{GM}{R^{2}}

g=\frac{6.67259 \times 10^{-11}\times 5.96\times 10^{24}}{(6.37\times 10^{6})^{2}}

g=9.79ms^{-2}

A object of mass m at the surface of earth experiences a force mg

3 0
3 years ago
Eli and Andy want to find out which of the two is stronger. Eli pushes a table with a force of 120 newtons while Andy pushes the
Sliva [168]

Answer:

B.  0.50 meters/second^2

Explanation:

Given:

  • mass of table (m) = 10.0 kg
  • Eli's force (F1) = 120 N
  • Andy's force (F2) = -125 N

Arranging Formulas and Substituting Values, Part 1:

  • F = F1 + F2
  • F = 120 + (-125)
  • F = -5 N
  • The -5 means that the table will move along the direction of the force applied by Andy.

Arranging Formulas and Substituting Values, Part 2:

  • m * a = F
  • a = F / M
  • a = -5 / 10.0 kg
  • a = -0.5 m/s^2
3 0
3 years ago
Read 2 more answers
A 460 nm monochromatic light is split into two beams. The two beams arrive at a point on a screen with a path difference of 920n
VladimirAG [237]

Answer:

phase difference \Delta \Phi = 12.566

Explanation:

Phase difference is expressed as \Delta \Phi

\Delta \Phi =\frac {2\pi}{\lambda} \Delta X

Where,

\Delta \Phi= phase difference

\lambda  wavelength = 460nm

\Delta X  path difference = 920 nm

\Delta \Phi =\frac {2\pi}{460} *920 = 4\pi

therefore

phase difference \Delta \Phi = 12.566

7 0
4 years ago
A car starts from rest with an acceleration of 8 m/s/s for a time of 4 s. What was the car's final velocity?
Aleks [24]
32m/s
8m/s x 4s= 32m/s
6 0
3 years ago
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