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3 years ago

10

Sobre un recipiente lleno de agua se sumerge completamente un objeto que desplaza un volumen de 0.096 metros cúbicos de agua hac

ia fuera del recipiente si tomamos en cuenta que densidad del agua es de 1000 kilogramos sobre metros cúbicos Determine la fuerza de empuje que ejerce el objeto sobre el agua

1 answer:

Licemer1 [7]3 years ago

7 0

Answer:

Fb = 941.76 [N]

Explanation:

La fuerza de flotacion se define como el producto de la densidad del liquido por la aceleración gravitacional y por el volumen desplazado

Fb = Ro*g*V

donde:

Fb = fuerza de flotacion [N] (unidades del Newtons)

Ro = densidad del liquido = 1000 [kg/m³]

g = aceleracion gravitacional = 9.81 [m/s²]

V = volumen desplazado = 0.096 [m³]

Reemplazando:

Fb = 1000*9.81*0.096

Fb = 941.76 [N]

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The attached diagrams is shown in the file below:

From there; taking moments about point A

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