Answer:
a) 16.4 m/s
b) 16.4 m/s
c) 16.4 m/s
Explanation:
a)
m = mass of the snowball = 0.690 kg
h = height of the cliff = 8.25 m
v₀ = initial speed of ball at the time of launch = 10.3 m/s
v = speed of the ball as it reach the ground
Using conservation of energy
initial kinetic energy + initial potential energy at the cliff = final kinetic energy just before reaching the ground
(0.5) m v₀² + mgh = (0.5) m v²
(0.5) v₀² + gh = (0.5) v²
(0.5) (10.3)² + (9.8 x 8.25) = (0.5) v²
v = 16.4 m/s
b)
As the launch angle is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the angle of launch.
v = 16.4 m/s
c)
As the mass is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the mass of the ball.
v = 16.4 m/s
Answer:
The gas state of water is water vapour. It is formed by boiling liquid water or from the sublimation of ice (sublimation is the process of converting a solid to a liquid). Hope this helps!
Answer:
honey mustard or chick fil a sauce their special sauce
Explanation:
Answer:
Explanation:
Since the surface is frictionless, momentum will be conserved. If the bullet of mass 
has an initial velocity 
and a final velocity 
and the block of mass 
has an initial velocity 
and a final velocity 
then the initial and final momentum of the system will be:
Since momentum is conserved, 
, which means:
We know that the block is brought to rest by the collision, which means 
and leaves us with:
which is the same as:
Considering the direction the bullet moves initially as the positive one, and writing in S.I., this gives us:
So kinetic energy of the bullet as it emerges from the block will be:
Answer:
The Force exerted by the two objects will be same and 4,401,189.49 × 10−11 N
Explanation:
Let m1 be the mass of the first object and m2 be the mass of the second object and the distance between them be d. Then
m1= 181kg
m2= 712 kg
d= 0.442 m
G is the gravitational Constant
According to Newtons Law Gravitational Force is given by
F=G m1 m2 /d²
F= 6.672 × 10−11 ×181×712/(0.442)²
F= 859,576.24 × 10−11/0.195364
F= 4,401,189.49 × 10−11 N
The Force exerted by the two masses on the third mass will be same and 4,401,189.49 × 10−11 N
