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ollegr [7]
3 years ago
8

What equation describes conservation of charge?

Physics
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

The equation which describes conservation of charge is Q_{initial} - Q_{final } = 0

Explanation:

The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.

let the sum of initial charges = Q_{initial}

let the sum of the final charges = Q_{final}

Q_{initial } = Q_{final}\\\\Q_{initial } - Q_{final} = 0

Therefore, the equation which describes conservation of charge is Q_{initial} - Q_{final } = 0

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A 0.690 kg snowball is fired from a cliff 8.25 m high with an initial velocity of 10.3 m/s, directed 32.0° above the horizontal.
Lana71 [14]

Answer:

a) 16.4 m/s

b) 16.4 m/s

c) 16.4 m/s

Explanation:

a)

m = mass of the snowball = 0.690 kg

h = height of the cliff = 8.25 m

v₀ = initial speed of ball at the time of launch = 10.3 m/s

v = speed of the ball as it reach the ground

Using conservation of energy

initial kinetic energy + initial potential energy at the cliff = final kinetic energy just before reaching the ground

(0.5) m v₀² + mgh = (0.5) m v²

(0.5) v₀² + gh = (0.5) v²

(0.5) (10.3)² + (9.8 x 8.25) = (0.5) v²

v = 16.4 m/s

b)

As the launch angle is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the angle of launch.

v = 16.4 m/s

c)

As the mass is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the mass of the ball.

v = 16.4 m/s

7 0
4 years ago
The gas state of water
salantis [7]

Answer:

The gas state of water is water vapour. It is formed by boiling liquid water or from the sublimation of ice (sublimation is the process of converting a solid to a liquid). Hope this helps!

4 0
3 years ago
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What sauce goes best with chicky nuggies
Sever21 [200]

Answer:

honey mustard or chick fil a sauce their special sauce

Explanation:

6 0
3 years ago
A 10-g bullet moving horizontally with a speed of 2.0 km/s strikes and passes through a 4.0-kg block moving with a speed of 4.2
SVEN [57.7K]

Answer:

K=512J

Explanation:

Since the surface is frictionless, momentum will be conserved. If the bullet of mass m_1 has an initial velocity v_{1i} and a final velocity v_{1f} and the block of mass m_2 has an initial velocity v_{2i} and a final velocity v_{2f} then the initial and final momentum of the system will be:

p_i=m_1v_{1i}+m_2v_{2i}

p_f=m_1v_{1f}+m_2v_{2f}

Since momentum is conserved, p_i=p_f, which means:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}

We know that the block is brought to rest by the collision, which means v_{2f}=0m/s and leaves us with:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}

which is the same as:

v_{1f}=\frac{m_1v_{1i}+m_2v_{2i}}{m_1}

Considering the direction the bullet moves initially as the positive one, and writing in S.I., this gives us:

v_{1f}=\frac{(0.01kg)(2000m/s)+(4kg)(-4.2m/s)}{0.01kg}=320m/s

So kinetic energy of the bullet as it emerges from the block will be:

K=\frac{mv^2}{2}=\frac{(0.01kg)(320m/s)^2}{2}=512J

6 0
4 years ago
Objects with masses of 181 kg and 712 kg are separated by 0.442 m. A 72.6 kg mass is placed midway between them. 0.442 m b b 181
Semmy [17]

Answer:

The Force exerted by the two objects will be same and 4,401,189.49  × 10−11 N

Explanation:

Let m1 be the mass of the first object and m2 be the mass of the second object and the distance between them be d. Then

m1= 181kg

m2= 712 kg

d= 0.442 m

G is the gravitational Constant

According to Newtons Law Gravitational Force is given by

F=G m1 m2 /d²

F= 6.672 × 10−11 ×181×712/(0.442)²

F=  859,576.24  × 10−11/0.195364

F=  4,401,189.49  × 10−11 N

The Force exerted by the two masses on the third mass will be same and 4,401,189.49  × 10−11 N

5 0
3 years ago
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