What is the range for the graph shown? A) -3_ B) -3 and 2 C) -3_ D) -2 _
1 answer:
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Answer:
Step-by-step explanation:
From the given information:
The null and the alternative hypothesis can be well written as:
Given that:
n = 200
x = 135
Alpha ∝ = 0.05 level of significance
Then;
⇒
= 200 × 0.6 × (1 -0.6)
= 200 × 0.6 × 0.4
= 48 ≥ 10
The sample proportion
= 0.675
The test statistics
Z = 2.165
The P-value = P(Z > 2.165)
= 1 - P(Z < 2.165)
From the z tables
= 1 - 0.9848
= 0.0152
Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).
Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6
Answer:
Hello some parts of your question is missing below is the missing part
answer : A) p-value = 0.0019 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Step-by-step explanation:
A) using a 0.05 level of significance and test for independence of the quality of management
Test statistic : ∑ ( Oi - Ei )^2 / Ei
= [(40-35)^2 / 35 ] + [(25-24.5)^2 / 24.5 ] + [(5-10.5)^2 / 10.5] + [(35-40)^2 / 40] + [(35-28)^2 / 28] + [(10-12)^2 / 12] + [ (25-25)^2 / 25 ] + [(10-17.5)^2 / 17.5 ] + [(15-7.5)^2 / 7.5] = 17.03
p-value = 0.0019
Df = 4 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
