Answer:
C) In[reactant] vs. time
Explanation:
For a first order reaction the integrated rate law equation is:
![A = A_{0}e^{-kt}](https://tex.z-dn.net/?f=A%20%3D%20A_%7B0%7De%5E%7B-kt%7D)
where A(0) = initial concentration of the reactant
A = concentration after time 't'
k = rate constant
Taking ln on both sides gives:
![ln[A] = ln[A]_{0}-kt](https://tex.z-dn.net/?f=ln%5BA%5D%20%3D%20ln%5BA%5D_%7B0%7D-kt)
Therefore a plot of ln[A] vs t should give a straight line with a slope = -k
Hence, ln[reactant] vs time should be plotted for a first order reaction.
Answer:
0.2g
Explanation:
All radiodecay follows the 1st order decay equation
A = A₀e^-kt
A => Activity at time (t)
A₀ => Initial Activity at time = 0
k => decay constant for isotope
T => time in units that match the decay constant
Half-Life Equation => kt(½) = 0.693 => k = 0.693/34 min = 0.0204min¹
A = A₀e^-kt = (26g)e^-(0.0204/min)(238min) = (26g)(0.0078) = 0.203g ~ 0.2g (1 sig fig).
The aluminum sulfate stock solution should the chemist pour out is 219.8 ml
Complete Question
A chemist must prepare 400 mL of 1.00M aqueous aluminum sulfate working solution. He'll do this by pouring out 1.82 mol/L aqueous aluminum sulfate stock solution into a graduated cylinder and diluting it with distilled water. How many mL of the aluminum sulfate stock solution should the chemist pour out?
The aluminum sulfate stock solution should the chemist pour out is 219.8 ml
Given:
V1 = 400ml, M1 = 1 M, V2 = ?, M2 = 1.82 M
Hence, the relation between molarity and volume is as follows.
M1V1 = M2V2
1.00M x 400ml = 1.82 x V2
V₂ = 219.8 ml
Thus, we can conclude that 219.8 ml of the aluminum sulfate stock solution should the chemist pour out.
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There is no state that has the highest density. the state of matter is measured by temperature and pressure..