Thermal energy lab report

Perform the following calculations and give your answer with the correct number of significant figures:

GarryVolchara [31]

I think this is the answer try it

172.3995

4 0

3 years ago

This equation shows a ____ refer to this summary equation of photosynthesis to complete the sentences about chemical bonds and r

coldgirl [10]

The balanced chemical equation representing the process of photosynthesis is:

$6 CO_{2} +12H_{2}O-->C_{6}H_{12}O_{6}+6O_{2}$

The reactants in the process of photosynthesis are $CO_{2}$ and H $H_{2}O$ and the products of the reaction are glucose $C_{6}H_{12}O_{6}$ and oxygen $O_{2}$ . Oxygen is the nonpolar covalent gas which is released in the process of photosynthesis. The reactant $CO_{2}$ is a nonpolar covalent gas while the other reactant water $H_{2}O$ has polar covalent O-H bonds.

In the balanced chemical equation, the number of each type of element must be equal on both sides of the reaction.

6 0

3 years ago

List the major types of intermolecular forces in order of increasing strength. Is there some overlap? That is, can the strongest

Doss [256]

Answer:

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Explanation:

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6 0

3 years ago

A balloon occupies 1.50 L with 0.205 mol of carbon dioxide. How many moles would be required to increase the size of the balloon

Gekata [30.6K]

Answer:

0.683 moles of the gas are required

Explanation:

Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:

V₁n₂ = V₂n₁

Where V is volume and n are moles of 1, initial state and 2, final state of the gas.

Computing the values of the problem:

1.50Ln₂ = 5L*0.205mol

n₂ = 0.683 moles of the gas are required

8 0

3 years ago

When a 12.8 g sample of KCL dissolves in 75.0 g of water in a calorimeter the temp. drops from 31 Celsius to 21.6 Celsius. Calcu

Delicious77 [7]

Answer:

Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

7 0

3 years ago