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miss Akunina [59]
3 years ago
12

Is Aluminium a metalliod?

Physics
1 answer:
svlad2 [7]3 years ago
4 0
Aluminium is ordinarily classified as a metal. It is lustrous, malleable and ductile, and has high electrical and thermal conductivity. Like most metals, it has a close-packed crystalline structure<span> and forms a cation in aqueous solution.</span>
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A mass moves back and forth in simple harmonic motion with amplitude A and period T.
Sever21 [200]

a. 0.5 T

- The amplitude A of a simple harmonic motion is the maximum displacement of the system with respect to the equilibrium position

- The period T is the time the system takes to complete one oscillation

During a full time period T, the mass on the spring oscillates back and forth, returning to its original position. This means that the total distance covered by the mass during a period T is 4 times the amplitude (4A), because the amplitude is just half the distance between the maximum and the minimum position, and during a time period the mass goes from the maximum to the minimum, and then back to the maximum.

So, the time t that the mass takes to move through a distance of 2 A can be found by using the proportion

1 T : 4 A = t : 2 A

and solving for t we find

t=\frac{(1T)(2 A)}{4A}=0.5 T

b. 1.25T

Now we want to know the time t that the mass takes to move through a total distance of 5 A. SInce we know that

- the mass takes a time of 1 T to cover a distance of 4A

we can set the following proportion:

1 T : 4 A = t : 5 A

And by solving for t, we find

t=\frac{(1T)(5 A)}{4A}=\frac{5}{4} T=1.25 T

6 0
3 years ago
Explain relative velocity briefly​
fomenos

Answer:

Explanation:

Relative velocity is defined as the velocity of an object B in the rest frame of another object A.

4 0
3 years ago
Which of the following describes the image formed by a plane mirror?
Alenkasestr [34]

Answer:

Virtual and erect.

8 0
4 years ago
. If the student had a mass of 88.6 kg, what was his weight?
Andre45 [30]
<span>F = m*g = 88.6kg * 9.81 m/s^2 = 869 N (3 s.f.) 

The equation above is Newton's 2nd Law of Motion where g is the acceleration due to gravity near the Earth's surface.</span><span>
</span>
8 0
4 years ago
Read 2 more answers
Find net force acting on O
klemol [59]

The net force acting on the center O is 4.495 X 10⁹ N

<u>Explanation:</u>

Given:

Charge-

q₁ = 4C

q₂ = 3C

q₃ = -5C

q₄ = 2C

q₅ = 1C

Side of the square = 4cm

Net force acting on the center, F = ?

Length of the side of the square is 4cm

The length of the diagonal will be 4√2

The length of half diagonal = 4√2 / 2 = 2√2

Force acting on the center of the square is:

F = k({\frac{Qq_1}{r^2} + \frac{Qq_2}{r^2} + \frac{Qq_3}{r^2} + \frac{Qq_4}{r^2} )\\\\\\

F = \frac{kQ}{r^2} (q_1 + q_2 + q_3 + q_4)

Here, k is coulomb's constant and the value is

k = 8.99 x 10⁹ N m2 / C2

On substituting the value, we get:

F = \frac{8.99 X 10^9 X 1}{(2\sqrt{2} )^2} ( 4C + 3C - 5C + 2C)\\\\F = \frac{8.99 X 10^9}{8} (4C)\\\\F = 4.495 X 10^9 N

Therefore, the net force acting on the center O is 4.495 X 10⁹ N

8 0
3 years ago
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