Answer:
V = 0.45 Volts
Explanation:
First we need to find the total current passing through the wire. That can be given by:
Total Current = I = (Current Density)(Surface Area of Wire)
I = (Current Density)(2πrL)
where,
r = radius = 1.5/2 mm = 0.75 mm = 0.75 x 10⁻³ m
L = Length of Wire = 6.5 m
Therefore,
I = (4.07 x 10⁻³ A/m²)[2π(0.75 x 10⁻³ m)(6.5 m)]
I = 1.25 x 10⁻⁴ A
Now, we need to find resistance of wire:
R = ρL/A
where,
ρ = resistivity of iron = 9.71 x 10⁻⁸ Ωm
A = Cross-sectional Area = πr² = π(0.75 x 10⁻³ m)² = 1.77 x 10⁻⁶ m²
Therefore,
R = (9.71 x 10⁻⁸ Ωm)(6.5 m)/(1.77 x 10⁻⁶ m²)
R = 0.36 Ω
From Ohm's Law:
Voltage = V = IR
V = (1.25 x 10⁻⁴ A)(0.36 Ω)
<u>V = 0.45 Volts</u>
Answer:
Part a)

Part b)

Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
Explanation:
Part a)
Let say the collision between Moose and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part b)
Let say the collision between Camel and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
Scientists think the solar system formed around 4.6 billion years ago from a cloud of dust and gas known as a solar nebula. Gravity collapsed the material on itself as it began to spin. This formed the sun in the middle. The planets formed when rock joined together in clumps and became bigger and bigger. And thus, our solar system was formed. Hope this helped
Answer:Consider a rechargeable lithium cell that is to be used to power a camcorder. Construct a problem in which you calculate the internal resistance of the cell during normal operation. Also, calculate the minimum voltage output of a battery charger to be used to recharge your lithium cell. Among the things to be considered are the emf and useful terminal voltage of a lithium cell and the current it should be able to supply to a camcorder.
Explanation:
Weak base i think since it’s a lower ph