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2 years ago

What force stops a car from sinking into the road surface?

Physics

2 answers:

Strike441 [17]2 years ago

8 0

Answer:

Explanation:

There are so many factors which works to stop a car from sinking into road surface. One is reaction force other factors are density of material from which the car is made of, mass and shape of car.but the most important force is the reaction force. According to the Newton's 3rd law of motion:- every force have equal force acting in opposite direction.

mariarad [96]2 years ago

4 0

I believe it's technically referred to as the Normal force.
However I like to think of it as the reaction force, as it is the force that is a result of obeying Newton's 3rd law ("<span>For every action, there is an equal and opposite reaction"). The upward force from the ground is the reaction to the downward force of gravity.</span>

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Could you please assist me, thank you kindly.

Bogdan [553]

In Newton's Third law of motion, the 'action' and 'reaction' forces act on different objects. That's why they don't cancel each other out and always result in zero force.

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2 years ago

I need to submit my homework in an hour, this is only question i cant solve. someone pls help!!

Sauron [17]

Hope this helps.......☺

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2 years ago

Find the acceleration of the blocks when the system is released. The coefficient of kinetic friction is 0.4, and the mass of eac

grin007 [14]

Answer:

a = 4.9(1 - sinθ - 0.4cosθ)

Explanation:

Really not possible without a complete setup.

I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g

F = ma

mg - mgsinθ - μmgcosθ = (m + m)a

mg(1 - sinθ - μcosθ) = 2ma

½g(1 - sinθ - μcosθ) = a

maximum acceleration is about 2.94 m/s² when θ = 0

acceleration will be zero when θ is greater than about 46.4°

8 0

2 years ago

It has been suggested, and not facetiously, that life might have originated on Mars and been carried to Earth when a meteor hit

damaskus [11]

Answer:

$a=3125000 m/s^2\\a=3.125*10^6 m/s^2$

Acceleration, in m/s, of such a rock fragment = $3.125*10^6m/s^2$

Explanation:

According to Newton's Third Equation of motion

$V_f^2-V_i^2=2as$

Where:

$V_f$ is the final velocity

$V_i$ is the initial velocity

a is the acceleration

s is the distance

In our case:

$V_f=V_{escape}, V_i=0,s=4 m$

So Equation will become:

$V_{escape}^2-V_i^2=2as\\V_{escape}^2-0=2as\\V_{escape}^2=2as\\a=\frac{V_{escape}^2}{2s}\\a=\frac{(5*10^3m)^2}{2*4}\\a=3125000 m/s^2\\a=3.125*10^6 m/s^2$

Acceleration, in m/s, of such a rock fragment = $3.125*10^6m/s^2$

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2 years ago

Why cant soy sauce freeze

juin [17]

The salt content in soy

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2 years ago

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