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3 years ago

What force stops a car from sinking into the road surface?

Physics

2 answers:

Strike441 [17]3 years ago

8 0

Answer:

Explanation:

There are so many factors which works to stop a car from sinking into road surface. One is reaction force other factors are density of material from which the car is made of, mass and shape of car.but the most important force is the reaction force. According to the Newton's 3rd law of motion:- every force have equal force acting in opposite direction.

mariarad [96]3 years ago

4 0

I believe it's technically referred to as the Normal force.
However I like to think of it as the reaction force, as it is the force that is a result of obeying Newton's 3rd law ("<span>For every action, there is an equal and opposite reaction"). The upward force from the ground is the reaction to the downward force of gravity.</span>

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A Gaussian surface in the form of a hemisphere of radius R = 3.04 cm lies in a uniform electric field of magnitude E = 1.64 N/C.

Likurg_2 [28]

Answer:

Part a)

$\phi = -4.76 \times 10^{-3} Nm^2/C$

Part b)

$\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C$

Explanation:

Part a)

Electric flux entering into the base

so it is given as

$\phi = E.A$

$\phi = - EA$

$\phi = -(1.64)(\pi r^2)$

$\phi = -(1.64)(\pi\times 0.0304^2)$

$\phi = -4.76 \times 10^{-3} Nm^2/C$

Part b)

Now since we know that there is no enclosed charge in the hemisphere

so net flux must be zero

$\phi_{curved} + \phi_{flat} = 0$

$\phi_{curved} - 4.76 \times 10^{-3} = 0$

$\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C$

7 0

2 years ago

1. Each of four boys were given

GalinKa [24]

Answer:

the answer is A because

from tate 4 dozen is 48 and from joe the sixth multiple of eight is 48

3 0

3 years ago

The Cosmoclock 21 Ferris wheel in Yokohama City, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which

emmainna [20.7K]

Answer:

Explanation:

A ) angular velocity ω = 2π / T

= 2 x 3.14 / 60

= .10467 rad / s

linear velocity v = ω R

= .10467 x 50

= 5.23 m / s

centripetal force = m v² / R

= mg v² / gR

= 834 x 5.23² / 9.8 x 50

= 46.55 N

B )

apparent weight

= mg - centripetal force

= 834 - 46.55

= 787.45 N

C ) apparent weight

= mg + centripetal force

= 834 + 46.55

= 880.55 N.

D )

For apparent weight to be zero

centripetal force = mg

mg = mv² / R

v² = gR

= 9.8 x 50

= 490

v = 22.13 m /s

time period of revolution

= 2π R /v

2 x 3.14 x 50 / 22.13

= 14.19 s

8 0

3 years ago

Atoms with certain characteristics are radioactive. Which of those below will

Andrei [34K]

Answer:

D. all atoms with an atomic number over 83

8 0

2 years ago

What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh

Goshia [24]

Answer:

a) $R_s = 0.092$

b) $R_p = 0.085$

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

$R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2$

using snell's law to calculate θ t

$sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}$

$cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}$

a) $R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2$

$R_s = 0.092$

b) $R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2$

$R_p = 0.085$

3 0

3 years ago