Answer:
Explanation:
To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.
For the wavelength;
Recall that, the separation between two successive max. and min. intensity points are 
Thus; for both speakers; the wavelength of the sound is:


λ = 80 cm
The relation between the path difference(Δx) and the phase difference(Δ∅) is:

where;
Δx = 10 cm
λ = 80 cm
Δ∅ = π rad
∴







Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm
Thus, we have:



∴
The amplitude of the sound wave if the two speakers are placed side-by-side is:



A = 0.765a
Answer:
<h3>The answer is 500 km </h3>
Explanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
<h3>distance = average velocity × time</h3>
From the question
average speed = 250 km/h
time = 2 hrs
We have
distance = 250 × 2
We have the final answer as
<h3>500 km</h3>
Hope this helps you
Answer:
9.6J+88.2J=97.8J
Explanation:
Here the velocity of the seagull is given,mass is given and its height.
We have to find its mechanical energy my friend.
Mechanical energy=kinetic energy + potential energy.
First we will find kinetic energy.
For calculating kinetic energy we need mass and velocity,which are given here.
So, Ek=

So by substituting the values we get 9.6J.
Now we find the potential energy which is mgh.
By substituting the values we get 88.2J.
Then we add both of those and get 97.8J
I hope this satisfies you and make sure you contact me if it doesn't
Answer:
-0.912 m/s
Explanation:
When the package is thrown out, momentum is conserved. The total momentum after is the same as the total momentum before, which is 0, since the boat was initially at rest.

where
are the mass of the child, the boat and the package, respectively.
are the velocity of the package and the boat after throwing.


