The primary factor that determines the elution order of compounds during gas chromatography, is the boiling point of the compounds. The lower the boiling point of a substance, the shorter retention time the substance will have. The retention time is the time it takes for the substance to be injected into the GC and reach the detector.
A lower boiling compound will elute faster (shorter retention time) than a higher boiling compound. The reason for this is the mobile phase of GC is a gas while the stationary phase is a liquid. Therefore, the more time a compound spends in the mobile phase, the faster it will elute.
The boiling point of anisole and d-limonene are 153.8 °C and 176 °C, respectively. Therefore, anisole will have a shorter retention time since it has the lower boiling point.
After 3 half life periods you would have 5 grams of krypton left because half of 40 is 20 half of 20 is 10 and half of 10 is 5
Explanation:
Ethanoic acid is a weak acid and dissociates:
C
H
3
C
O
O
H
⇌
C
H
3
C
O
O
−
+
H
+
For which
K
a
=
[
C
H
3
C
O
O
−
]
[
H
+
]
[
C
H
3
C
O
O
H
]
=
1.8
×
10
−
5
Please remember that these are equilibrium concentrations .
p
K
a
=
−
log
K
a
=
−
log
[
1.8
×
10
−
5
]
=
4.74
n
=
c
×
v
∴
n
C
H
3
C
O
O
H
=
0.20
×
200.0
1000
=
0.04
Answer:
The answer would be chytrids.
<u>Answer:</u> The correct answer is Option D.
<u>Explanation:</u>
To calculate the hybridization of
, we use the equation:
![\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
where,
V = number of valence electrons present in central atom (S) = 6
N = number of monovalent atoms bonded to central atom = 0
C = charge of cation = 0
A = charge of anion = 0
Putting values in above equation, we get:
![\text{Number of electron pair}=\frac{1}{2}[6]=3](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5B6%5D%3D3)
The number of electron pair around the central metal atom are 3. This means that the hybridization will be
and the electronic geometry of the molecule will be trigonal planar.
Hence, the correct answer is Option D.