All categories

3 years ago

Which wave is used to identify the heat given off by distant objects in space

Chemistry

1 answer:

kicyunya [14]3 years ago

6 0

Sorry if i’m late but your answer should be infrared

You might be interested in

A peregrine falcon can travel 537,600 furlong/fortnight. A race car travels 212ft/s. A spider can jump with a maximum velocity o

o-na [289]

Convert everything to one base unit (let's do ft/s in this case)
There are 660 ft in a furlong and 2 weeks or 1209600 seconds in a fortnight
Multiply 537,600furlong and 660 ft/furlong and divide by 1209600 to get 293.333ft/s

The race car is already in ft/s

There are 30.48 cm in 1 foot and 3600 seconds in 1 hour. Multiply 9,000,000 by 1/30.48 and 1/3600 to get 82.02ft/s

THe peregrine falcon is the fastest

6 0

4 years ago

What mass of iron(II) oxide must be used in the reaction given by the equation below to release 44.7 kJ? 6FeO(s) + O2(g) => 2

zavuch27 [327]

<u>Answer:</u> The mass of iron (II) oxide that must be used in the reaction is 30.37

<u>Explanation:</u>

The given chemical reaction follows:

$6FeO(s)+O_2(g)\rightarrow 2Fe_3O_4(s);\Delta H^o=-635kJ$

By Stoichiometry of the reaction:

When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.

So, when 44.7 kJ of energy is released, $\frac{6}{635}\times 44.7=0.423mol$ of iron (II) oxide is reacted.

Now, calculating the mass of iron (II) oxide by using the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of iron (II) oxide = 0.423 moles

Molar mass of iron (II) oxide = 71.8 g/mol

Putting values in above equation, we get:

$0.423mol=\frac{\text{Mass of FeO}}{71.8g/mol}\\\\\text{Mass of FeO}=(0.423mol\times 71.8g/mol)=30.37g$

Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37

7 0

4 years ago

Where else do you see Force & Motion in real-world experiences?

Paladinen [302]

Answer:

a boy pulling a toy train, the boy is

interacting with an object while applying a force to it,

another example of contact forces is friction.

Explanation:

A contact force is when two interacting

objects

(btw love your pfp)

4 0

3 years ago

Read 2 more answers

In your OWN words...HOW is Hydropower produced?

Lapatulllka [165]

Well by rushing water or moving water

8 0

3 years ago

What would happen to the rate of a reaction with rate law rate = k [NO]^2[H2] if

Ede4ka [16]

The rate of a reaction would be one-fourth.

<h3>Further explanation</h3>

Given

Rate law-r₁ = k [NO]²[H2]

Required

The rate of a reaction

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.

Can be formulated:

Reaction: aA ---> bB

$\large{\boxed{\boxed{\bold{v~=~-\frac{\Delta A}{\Delta t}}}}$

$\large{\boxed{\boxed{\bold{v~=~+\frac{\Delta B}{\Delta t}}}}$

The concentration of NO were halved, so the rate :

$\tt r_2=k[\dfrac{1}{2}No]^2[H_2]\\\\r_2=\dfrac{1}{4}k.[No]^2[H_2]\\\\r_2=\dfrac{1}{4}r_1$

3 0

3 years ago

Read 2 more answers