Which wave is used to identify the heat given off by distant objects in space
1 answer:
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Answer:
<em>56.4 m</em>
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Explanation:
volume increases by factor of 6, i.e = 6
Initial temperature T1 at bottom of lake = 5.24°C = 278.24 K
Final temperature T2 at top of lake = 18.73°C = 291.73 K
NB to change temperature from °C to K we add 273
Final pressure P2 at the top of the lake = 0.973 atm
Initial pressure P1 at bottom of lake = ?
Using the equation of an ideal gas
=
P1 = =
P1 = 5.57 atm
5.57 atm = 5.57 x 101325 = 564380.25 Pa
Density Ρ of lake = 1.02 g/ = 1020 kg/
acceleration due to gravity g = 9.81
Pressure at lake bottom = pgd
where d is the depth of the lake
564380.25 = 1020 x 9.81 x d
d = = <em>56.4 m</em>
Answer:
Explanation:
Given:
Depth = h
Width = w
Length = 1
Now,
Let ρ be the density of water
Thus,
Pressure force at the bottom will be
= Pressure × Area
= ρgh × (w × 1)
also,
Pressure force at the sides will be =
ρgh × (h × w)
Therefore,
The ratio of the pressure force at the bottom to the pressure force on the side of the tank will be
=
=