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3 years ago

THIS NOT MY WORK. its for my sister. HELP HER

Chemistry

2 answers:

Stolb23 [73]3 years ago

5 0

Answer:

Your answer will be b(molten material from the outer core makes its way to the surface of earth)

Explanation:

Elina [12.6K]3 years ago

4 0

Answer:

Explanation:

I'm pretty sure molten material comes from the inner core. I think you can search up this though, try to find where molten material comes from. Goodluck!

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What is the Molarity of a solution of HNO3 if it contains 12.6 moles in a 0.75 L solution? *

Korolek [52]

Answer:

M = 16.8 M

Explanation:

Data: HNO3

moles = 12.6 moles

solution volume = 0.75 L

Molarity is represented by the letter M and is defined as the amount of solute expressed in moles per liter of solution.

$M=\frac{moles}{solution volume}$

The data is replaced in the given equation:

$M=\frac{12.6 mol}{0.75L}=16.8\frac{mol}{L}$

7 0

3 years ago

Read 2 more answers

Propane burns in oxygen to produce carbon dioxide and steam. The unbalanced equation for this reaction is: C3H8 + O2 → CO2 + H2O

NemiM [27]

Here is your answer

C3H8 + O2-----> CO2 + H2O

Balancing C atoms

C3H8 + O2------> 3CO2 + H2O

Balancing H atoms

C3H8 + O2------> 3CO2 + 4H2O

Balancing O atoms

C3H8 + $\bold{5}$ O2-------> $\bold{3}$ CO2 + $\bold{4}$ H2O

Hence the equation is balanced.

HOPE IT IS USEFUL

8 0

3 years ago

Hydrofluoric acid and Water react to form fluoride anion and hydronium cation, like this HF(aq) + H_2O(l) rightarrow F(aq) + H_3

maksim [4K]

Answer:

Kc = 1.09x10⁻⁴

Explanation:

HF = 1.62g

H₂O = 516g

F⁻ = 0.163g

H₃O⁺ = 0.110g

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

Kc = [H₃O⁺] [F⁻] / [HF]

Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M

[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M

Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]

7 0

3 years ago

DO TODAY, PLS HURRY I DONT HAVE TIME :C (10 points, this is science, and its a writeing Question) some animals survive winter by

Lerok [7]

Answer: Beavers

Explanation: they do not hibernate

hope it helps

7 0

3 years ago

A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor

AlexFokin [52]

Answer : The partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of $C_2HBrClF_3$ = 15.0 g

Mass of $O_2$ = 22.6 g

Molar mass of $C_2HBrClF_3$ = 197.4 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_2HBrClF_3$ and $O_2$ .

$\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole$

Now we have to calculate the mole fraction of $C_2HBrClF_3$ and $O_2$ .

$\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971$