Josh rolled a bowling ball down a lane in 2.5 seconds. The ball travelled at a constant acceleration of 1.8 m/s/s down the lane
1 answer:
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Answer:
a. t = 1.43 s
b. d = 7.88 m
Explanation:
a. The time of flight can be found using the following equation:
Where:
: is the final height = -10 m
: is the initial height = 0
: is the initial speed in the vertical direction = 0
g: is the acceleration due to gravity = 9.81 m/s²
By solving the above equation for "t" we have:
Hence, the ball will hit the ground in 1.43 s.
b. The distance in the horizontal direction can be found as follows:
Where:
x₀: is the initial position in the horizontal direction = 0
a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)
Therefore, the ball will travel 7.88 m before it hits the ground.
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Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that force on the passenger while moving in circle is given as
now variation in force is given as
here speed is constant
Part b)
Now if the variation in force is required such that r is constant then we will have
so we have
Part c)
As we know that time period of the circular motion is given as
so here if radius is constant then variation in time period is given as