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3 years ago

What do the water, nitrogen, and carbon cycle all have in common

Chemistry

1 answer:

Lelu [443]3 years ago

5 0

Answer:

How are the water carbon and nitrogen cycles related?

The three main cycles of an ecosystem are the water cycle, the carbon cycle and the nitrogen cycle. These three cycles working in balance are responsible for carrying away waste materials and replenishing the ecosystem with the nutrients necessary to sustain life.

Explanation:

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What identifies an ion

bezimeni [28]

Answer:

Identifying whether or not an element is an ion is a very simple process. Identify the charge of the element. ... The number of electrons is equal to the atomic number minus the charge of the atom. Refer to an element with either a positive or negative charge as an ion.

7 0

3 years ago

A shiny chunk of metal is found to have a mass of 37.28g. The metal is dropped into a graduated cylinder which contains 20.0 mL

Amanda [17]

Answer: The density of the material is 2.66 g/mL and it is likely this is made of Aluminum

Explanation:

The first step to know the material of the chunk of metal is to calculate its density. The general formula for density is P (density) = $\frac{m (mass)}{ v (volume)}$ . Moreover, in this case, it is known the mass is 37.28 g, but the volume is not directly provided. However, we know the water in the graduated cylinder had a volume of 20.0 mL and this increased to 34.0 mL when the chunk of metal is added, this means the volume of the metal is 14 mL (34.0 mL - 20.0 mL = 14 mL). Now let's calculate the density:

$P =$ $\frac{37.28g}{14.0mL}$

$P = 2.66 g/mL$

This means the density of this metal is 2.66 g/mL, which can be rounded as 2. 7 g/mL, and according to the chart, this is the density of aluminum. Therefore, this material of this chunk is aluminum.

6 0

4 years ago

What kind of ions are more prevalent in a basic solution? *

uranmaximum [27]

It's hydroxide ions because acids contain hydrogen ions

7 0

4 years ago

When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea

Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0

3 years ago

Calculate the maximum amount of CO2 that can be produced when 64.0 g of O2 and 64.0 g of CH3OH are mixed for the reaction 2 CH3O

Triss [41]

Answer:

58.7g

Explanation:

From the reaction equation, we can see that 3 moles of oxygen yielded 2 moles of carbon (iv) oxide. Let's keep this for later.

Now, we calculate the actual number of moles of oxygen reacted. This can be calculated as follows.

The number of moles of oxygen reacted = mass of oxygen reacted ÷ molar mass of oxygen molecule.

The mass of oxygen reacted is 64g. Now, the molar mass of the oxygen molecule can be calculated from the atomic mass of the oxygen atom. The atomic mass of the oxygen atom is 16 a.m.u .Hence the molar mass = 2 × 16 = 32g/mol.

The number of moles is thus 64 ÷ 32 = 2 moles.

We now calculate the number of moles of Carbon iv oxide yielded.

As said from the beginning of the equation, 3 moles oxygen yielded 2 moles 2 moles CO2. Hence, moles oxygen will yield (2 ×2) ÷ 3 = 4/3 moles O2.

Now we calculate the mass of CO2 yielded.

The mass is = number of moles of CO2 yielded × molar mass of CO2.

Molar mass of CO2 = 12 + 2(16) = 44g/mol.

The mass is thus = 4/3 × 44 = 58.66667g

5 0

3 years ago