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3 years ago

7

A loudspeaker has a circular opening with a radius of 0.1158 m. The electrical power needed to operate the speaker is 27.0 W. Th

e average sound intensity at the opening is 25.6 W/m2. What percentage of the electrical power is converted by the speaker into sound power

1 answer:

Vilka [71]3 years ago

3 0

Answer:

electrical power is converted by the speaker into sound power 17.25 %

Explanation:

given data

radius = 0.1158 m

power needed = 27.0 W

average sound intensity = 25.6 W/m²

solution

we know sound intensity that is

I = $\frac{power}{area}$ ...................1

power = intensity × area

Power = 25.6 × 4 ×π×r²

Power = 25.6 × 4 ×π×0.1158²

power = 4.313 W

so here electric power % into sound power

= $\frac{4.313}{25}$ × 100

= 17.25 %

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