A loudspeaker has a circular opening with a radius of 0.1158 m. The electrical power needed to operate the speaker is 27.0 W. Th
1 answer:
Answer:
electrical power is converted by the speaker into sound power 17.25 %
Explanation:
given data
radius = 0.1158 m
power needed = 27.0 W
average sound intensity = 25.6 W/m²
solution
we know sound intensity that is
I = ...................1
power = intensity × area
Power = 25.6 × 4 ×π×r²
Power = 25.6 × 4 ×π×0.1158²
power = 4.313 W
so here electric power % into sound power
= × 100
= 17.25 %
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